Answer:
The probability that he or she has gained weight, given that he or she takes more than one vitamin per day is 0.47
Step-by-step explanation:
Has Gained Weight Has Not Gained Weight
Does not take vitamins 52 19
Takes one vitamin per day 35 49
Takes more than one vitamin per day 72 80
We are supposed to find the probability that he or she has gained weight, given that he or she takes more than one vitamin per day
A= he or she has gained weight
B=he or she takes more than one vitamin per day
![P(A|B)=\frac{P(A \cap B)}{P(B)}](https://tex.z-dn.net/?f=P%28A%7CB%29%3D%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28B%29%7D)
![A \cap B = 72](https://tex.z-dn.net/?f=A%20%5Ccap%20B%20%3D%2072)
B = 72+80=152
So,![P(A|B)=\frac{72}{152}=0.47](https://tex.z-dn.net/?f=P%28A%7CB%29%3D%5Cfrac%7B72%7D%7B152%7D%3D0.47)
So, Option C is true
Hence the probability that he or she has gained weight, given that he or she takes more than one vitamin per day is 0.47
Answer:
![6a^3+45b](https://tex.z-dn.net/?f=6a%5E3%2B45b)
Step-by-step explanation:
![2a\times a\times 3a+b\times 45](https://tex.z-dn.net/?f=2a%5Ctimes%20a%5Ctimes%203a%2Bb%5Ctimes%2045)
![2a\times 1a\times 3a+b\times 45](https://tex.z-dn.net/?f=2a%5Ctimes%201a%5Ctimes%203a%2Bb%5Ctimes%2045)
![2\times 1\times 3 \times a \times a \times a+b\times 45](https://tex.z-dn.net/?f=2%5Ctimes%201%5Ctimes%203%20%5Ctimes%20a%20%5Ctimes%20a%20%5Ctimes%20a%2Bb%5Ctimes%2045)
![6a^3+b \times45](https://tex.z-dn.net/?f=6a%5E3%2Bb%20%5Ctimes45)
![=6a^3+45b](https://tex.z-dn.net/?f=%3D6a%5E3%2B45b)
Answer:
1+1=2
50+4=54
54+2=56
Step-by-step explanation:
This statement is actually false.
I have provided proof and wish you all the best (grade).