The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
Answer:
6 weeks
Step-by-step explanation:
Easier way to solve: If she takes 7 quizzes each week, 7 times something (amount of weeks) equals 42.
7 X <u>6</u> = 42
Solving with algebra: We know that hanna takes six quizzes a week and takes a total of 42 quizzes, therefore the unknown (x) is the amount of weeks she takes the quizzes.
Amount of weeks X amount of tests per weeks = 42 quizzes
<em>x </em>X 7 = 42
42/7 = 6
Answer:
(−2)(2)+(3)(−5)
=−19
Step-by-step explanation:
Answer:
The standard form of the quadratic equation is x² + 3·x - 4 = 0
Step-by-step explanation:
The standard form of a quadratic equation is a·x² + b·x + c = 0
Given that the expression of the quadratic equation is (x + 4)·(x - 1) = y, we can write the given expression in standard form by expanding, and equating the result to zero as follows;
(x + 4)·(x - 1) = x² - x + 4·x - 4 = x² + 3·x - 4 = 0
The standard form of the quadratic equation is x² + 3·x - 4 = 0
The graph of the equation created with MS Excel is attached
Perpendicular is the answer because for it to be perpendicular it has to be the opposite 3/4’s opposite is -4/3 which is why the answer is perpendicular
