Answer:
Answer:
£3692
Step-by-step explanation:
A = p(1 + r/n)^nt
Where,
A = future value
P = principal = £2350
r = interest rate = 4.2% = 0.042
n = number of periods = 1(annual)
t = time = 4 years
A = p(1 + r/n)^nt
= 2350(1 + 0.042/1)^1*4
= 2350(1 + 0.042)^4
= 2350(1.042)^4
= 2350(1.5789)
= 2770.42
A = £2770.42
Total years = 10
Remaining years = 10 – 4
= 6 years
Remaining 6 years
P = £2770.42
r = 4.9% = 0.049
n = 1
t = 6
A = p(1 + r/n)^nt
= 2770.42(1 + 0.049/1)^1*6
= 2770.42(1 + 0.049)^6
= 2770.42(1.049)^6
= 2770.42(1.3325)
= 3691.59
A = £3691.59
Approximately £3692
Thank you!
THE ANSWER YOU LOOKING FOR IS 21G
Answer:
x=0.5355 or x=-6.5355
First step is to: Isolate the constant term by adding 7 to both sides
Step-by-step explanation:
We want to solve this equation: 
On observation, the trinomial is not factorizable so we use the Completing the square method.
Step 1: Isolate the constant term by adding 7 to both sides
Step 2: Divide the equation all through by the coefficient of 
which is 2.
Step 3: Divide the coefficient of x by 2, square it and add it to both sides.
Coefficient of x=6
Divided by 2=3
Square of 3=
Therefore, we have:
Step 4: Write the Left Hand side in the form 
Step 5: Take the square root of both sides and solve for x
Answer:
1
Step-by-step explanation:
Solve. Remember to follow PEMDAS.
PEMDAS is the order of operation, and =
Parenthesis
Exponent (& Roots)
Multiplication
Division
Addition
Subtraction
First, divide 54 with -6:
54/(-6) = -9
Next, combine the terms.
10 + (-9) = 10 - 9 = 1
1 is your answer.
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If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
</span><span>
y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
</span><span>
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