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3 years ago

9

Help will give Brainly points

1 answer:

Anvisha [2.4K]3 years ago

7 0

Answer:

85

Step-by-step explanation:

Use the pythagorean theorem!

(think that is how you spell it )

Pythagorean theorem: a² + b² = c²

a and b are the numbers that you have in this example, c is the side you need!

75² + 40² = c²

5,625 + 1,600 = c²

7,225 = c²

$\sqrt{7,225} = \sqrt{c}^{2}$

(the square root and square cancel each other out)

85 = c

c = 85

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How to change from expo to radical form

Natalka [10]

Answer:

See below.

Step-by-step explanation:

If the exponent is a/b then a is the power and b is the value of the radical.

Example: x^2/3 = ∛x². 2 is the power and 3 is the radical.

Answers:

1) 7^2/3 = ∛7²

5) √3 = 3^1/2

9) (∛27)⁴ = 27^4/3 = 3^4 = 81.

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3 years ago

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Find the equation of the tangent at ( 0 , 2) to the circle with equation

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3 years ago

A projected image appears as an isosceles trapezoid.

Komok [63]

7x + 4 + 9x = 180
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3 years ago

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X3(2x2 + 3x) <br><br> a. 2x5 + 3x4 <br> b. 5x9 <br> c. 2x6 + 3x3 <br> d. 5x

Serhud [2]

Answer:

$2x^5+3x^4$

Step-by-step explanation:

$x^3\left(2x^2+3x\right)$

<u>Apply distributive law: </u> $a\left(b+c\right)=ab+ac$

$x^3\left(2x^2+3x\right)=x^3\times \:2x^2+x^3\times \:3x$

$x^3\times \:2x^2+x^3\times \:3x$

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3 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago