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Lina20 [59]
3 years ago
10

Evaluate 2y²(x+y) when x = 1 and y = 5

Mathematics
2 answers:
schepotkina [342]3 years ago
7 0

Answer:

12y²

Step-by-step explanation:

2y²(1 + 5)

1. Distribute

2y² + 10y²

2. Add Like Terms

12y²

maw [93]3 years ago
4 0

Answer:

\displaystyle 2y^2(x + y) = 300

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle 2y^2(x + y) \\ x = 1  \\ y = 5<em />

<em />

<u>Step 2: Evaluate</u>

  1. Substitute in variables [Equation]:                                                                   \displaystyle \displaystyle 2y^2(x + y) = 2(5)^2(1 + 5)
  2. Exponents:                                                                                                        \displaystyle \displaystyle 2y^2(x + y) = 2(25)(1 + 5)
  3. (Parenthesis) Add:                                                                                            \displaystyle \displaystyle 2y^2(x + y) = 2(25)(6)
  4. Multiply:                                                                                                             \displaystyle 2y^2(x + y) = 300
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