Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let = <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>
The z-score probability distribution for the sample mean is given by;
Z = ~ N(0,1)
where, = population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P( > 259 cm)
P( > 259 cm) = P( > ) = P(Z > -0.39) = P(Z < 0.39)
= <u>0.65173</u>
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
(oatmeal raisin) : (chocolate chip) = 5 : 6
(oatmeal raisin) = 35
(chocolate chip) =x
35 : x = 5 : 6
5x = 35*6
x= 35*6/5 =42 (chocolate chip)
combined amount = (oatmeal raisin) + (chocolate chip) = 35 +42 = 77
Answer is 77 cookies altogether.
Answer:
x = 41
Step-by-step explanation:
By the Angle Bisector Theorem, which basically states that EG / GD = EH / DH, we get this: 49 / 35 = 58.8 / (x + 1). Now, if we simplify, we get 7/5 = 58.8 / (x + 1). Cross-multiply to get 294 = 7x + 7, or 7x = 287. From here, it is obvious that x = 41.
Answer:
The value of Z is 109°
The value of Y is 38°
The value of X is 33°
Step-by-step explanation:
Answer:
9x10⁹= ¹0⁹
3x10⁷=30000000
9.45x10⁷=94500000
2.1x10²=210
Step-by-step explanation: