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3 years ago

X^4 - 17x^2 + 16 hhhhhhhhhhhhhhhhhhhhh

Mathematics

1 answer:

defon3 years ago

5 0

Answer:

Step-by-step explanation:

If the question is to factorize

$x^4-17x^2+16\\\\x^4-x^2-16x^2+16\\\\=x^2(x^2-1)-16(x^2-1)\\\\=(x^2-1)(x^2-16)\\\\=(x+1)(x-1)(x-4)(x+4)\\$

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Lamar wanted to explain why the measure of angle 5 is equal to the sum of the measures of angles 1 and 3. Which geometry concept

andreyandreev [35.5K]

In this question, angle 5 and angle 2 are linear pair. And angles of linear pair are supplementary angles .

Therefore

$\angle 5 + \angle 2=180$

And sum of interior angles of a triangle is 180 degree, that is

$\angle 1 + \angle 2 + \angle 3 =180$

SInce both the equations have 180 in the right side, left side of both equations are equal too . That is

$\angle 5 + \angle 2 = \angle 1 + \angle 2 + \angle 3$

Which gives

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So the correct option is A .

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3 years ago

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The lifetimes of a certain type of light bulbs follow a normal distribution. If approximately 2.5% of the bulbs have lives excee

spin [16.1K]

Answer:

Mean = 339 hours

Standard deviation = 54 hours

Step-by-step explanation:

We are given that approximately 2.5% of the bulbs have lives exceeding 445 hours

So,P(x>445) = 0.025

P(x<445) =1- 0.025 =0.975

z value for 0.975 is 1.96

Formula : $z=\frac{x-\mu}{\sigma}$

So, $1.96=\frac{445-\mu}{\sigma}$

$1.96 \sigma =445-\mu$ --A

Now we are given that approximately 16% have lives exceeding 393 hours,

So,P(x>393) = 0.16

P(x<393) =1- 0.16 =0.84

z value for 0.84 is 1

Formula : $z=\frac{x-\mu}{\sigma}$

So, $1=\frac{393-\mu}{\sigma}$

$1 \sigma =393-\mu$ ---B

Solve A and B

Substitute the value of $\sigma$ from B in A

$1.96 (393 -\mu) =445-\mu$

$770.28 -1.96\mu=445-\mu$

$770.28 -445=1.96\mu-\mu$

$325.28=0.96\mu$

$\frac{325.28}{0.96}=\mu$

$338.83=\mu$

Substitute the value in B

$\sigma =393-338.83$

$\sigma =54.17$

So, mean = 339 hours

Standard deviation = 54 hours

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3 years ago

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The area of the circle is

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Dude this app is for homework purposes. Not to chat with people.

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Answer:

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