If we consider the reaction CH₃O⁻ + H₂O ⇌ CH₃OH + OH⁻ in the forward direction, the base in the reaction is CH₃O⁻
A compound can be acidic, basic or neutral in nature. Basicity of the compound is determined when it either releases hydroxide ions, donates electrons or else accepts the protons from a compound.
In the reaction CH₃O⁻ + H₂O ⇌ CH₃OH + OH⁻:
CH₃O⁻ accepts proton or [H+] ion to become CH₃OH. Thus, CH₃O⁻ is the base in the reaction
H₂O donate [H+] ion or proton, therefore H2O change into OH-. Thus, H₂O is an acid in the reaction.
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Answer : The water's temperature change will be,
Explanation : Given,
Density of water = 0.998 g/mL
Volume of water =
(conversion used : 1 L = 1000 mL)
Specific heat of water =
Heat absorbed =
(conversion used : 1 kJ = 1000 J)
First we have to determine the mass of water.
Now we have to calculate the change in temperature of water.
Formula used :
where,
Q = heat absorbed by water
m = mass of water
= specific heat of water
= change in temperature
Now put all the given value in the above formula, we get:
Therefore, the water's temperature change will be,
Answer:
(a) 0.575 m;
(b) 0.527 m
Explanation:
Let's use the freezing point depression law in each of these cases.
(a) According to the law:
Rearrange the equation for molality, b:
NaCl is an ionic substance, 1 mole of it dissociates into 2 moles of ions, sodium ion and chloride ion, this means the van 't Hoff factor i = 2.
Here:
is the initial freezing point of water,
is the final freezing point of water.
For water:
Applying the equation
(b) Applying the same equation for the same salt and the same conditions, except a new freezing point, we would expect to obtain:
To produce glucose from carbon dioxide, 6 moles of carbon dioxide are required per mole of glucose.
Mass of carbon dioxide required:
6 x 44.01
= 264.06 grams
Answer: Atoms lose energy as a gas changes to a solid.
Explanation: