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elixir [45]
3 years ago
10

Convert 5.0 x 1027 r.p. of copper to moles of copper.

Chemistry
1 answer:
PtichkaEL [24]3 years ago
3 0
Convert 5.0 to 1027 an you should get your answer
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Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
slava [35]

Answer:

pH of resulting solution = 7.98

Explanation:

The balanced equation  

HA + NaOH - Na+ + A- + H2O

Number of moles of A = Number of moles of HA  = Number of moles of NaOH

= 35.8/1000 * 0.020 = 0.000716 mol

Initial concentration of A = 0.000716/0.0608 = 0.01178 M

pKb = 14 – pKa = 14 -3.9 = 10.1

Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11

Kb = [HA][OH-]/[A-]

Kb = a^2/(0.01178 -a) = 7.943 * 10^-11

a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0

a = 9.673 * 10^-7

OH- = a = 9.673 * 10^-7 M

pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02

pH = 14-6.02 = 7.98

8 0
3 years ago
2
Gemiola [76]

Answer:

the physical and chemical properties of the products are different from the reactants

Explanation:

A chemical reaction involves the chemical combination of two or more elements/compounds called Reactants to give one or more different elements/compounds called Products. A chemical reaction occurs in such a way that the atoms of the reactants are restructured to form product(s) that is/are entirely different from the reactants.

In a chemical reaction, the physical and chemical properties of the products differ from that of the reactants since different chemical compounds/elements are formed as products. The physical properties of a substance, which include colour, melting and boiling point etc. will differ in the reactants and products formed. Also, the chemical structure and identity of the reactants will be changed to give rise to a different chemical property in the products.

7 0
3 years ago
Balance <br> Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O
Delicious77 [7]

Equation balance:

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

2Al(OH)3+3H2SO4

H=12

SO4=3

O=6

Al=2

Al2(SO4)3+6H2O

H=12

SO4=3

O=6

Al=2

8 0
3 years ago
Given 6193 mL of a gas at 62.3 °C. What is its volume at 38.1 °C?
Luden [163]

Answer:

5746.0 mL.

Explanation:

We can use the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have two different values of V and T:

<em>V₁T₂ = V₂T₁</em>

<em></em>

V₁ = 6193.0 mL, T₁ = 62.3°C + 273 = 335.3 K.

V₂ = ??? mL, T₂ = 38.1°C + 273 = 311.1 K.

<em>∴ V₂ = V₁T₂/T₁ </em>= (6193.0 mL)(311.1 K)/(335.3 K) = <em>5746.0 mL.</em>

5 0
3 years ago
I really need help on this and it's due in 30 minutes please, please.
Lorico [155]

Answer:

did you pass? I kinda wanna know.

4 0
3 years ago
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