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3 years ago

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I really need help with this and fast, any you could please answer I would really appreciate it, also please only answer if you

actually do know the answer because people have been taking advantage of me because I’m giving a lot of points and this is due in like 30 min

1 answer:

deff fn [24]3 years ago

5 0

there are 2 types of mixture

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Based on your own understanding and information in this lesson, what characteristics of the Confederate States of America made i

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The main characteristic of the Confederate States of America that made it a confederal government <span>when compared to the government of the United States was that its central power was much weaker. </span>

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3 years ago

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How many moles are in 23 g of LICI

Leya [2.2K]

Answer:

42.394

Explanation:

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3 years ago

How does a scientist make two solutions with the same molarity? A By dissolving the maximum amount of each substance in the B. B

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4 years ago

Phosgene is formed from carbon monoxide and chlorine. At 611 oC, Kc is approximately 16.5 M-1 or L/mol. Calculate Kp (in atm-1)

defon

Answer:

Kp is 0.228/atm

Explanation:

This is the reaction:

CO + Cl<u>₂</u> → CCl₂O

1 mol of carbon monoxide and 1 mol of chlorine produce 1 mol of phosgene.

Formula for Kp which derivates from Kc is:

Kp = Kc (R.T)ⁿᵇ ⁻ ⁿᵃ

Δп = nb (moles in the products) - nₐ(moles in the reactants)

Δп = 1 - 2 = -1

T is T° in K → T°C + 273 = 611°C +273 = 884K

R → Universal constant gas → 0.082 L.atm/mol.K

We replace the data: Kp = 16.5 L/mol (0.082 . 884K)⁻¹ → 0.228/atm

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4 years ago

The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sample o

adoni [48]

Answer:

550 m/s

Explanation:

The average molecular speed (v) is the speed associated with a group of molecules on average. We can calculate it using the following expression.

$v = \sqrt{\frac{3 \times R \times T}{M} }$

where,

R: ideal gas constant

T: absolute temperature

M: molar mass of the gas

We can use the info of argon to calculate the temperature for both samples.

$T = \frac{v^{2} \times M}{3 \times R} = \frac{(391m/s)^{2} \times 39.95g/mol}{3 \times 8.314J/k.mol} = 2.45 \times 10^{5} K$

Now, we can use the same expression to find the average molecular speed in a sample of Ne gas.

$v = \sqrt{\frac{3 \times R \times T}{M} } = \sqrt{\frac{3 \times (8.314J/k.mol) \times 2.45 \times 10^{5}K }{20.18g/mol} } = 550 m/s$

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3 years ago