Why was UwU createdwwwwwwwwwwwwwwwwwwwwwwwwwwwww

The following reaction, catalyzed by iridium, is endothermic at 700 K: CaO(s) + CH4(g) + 2H2O (g) → CaCO3 (s) + 4H2 (g) For the

arsen [322]

Answer:

A. Increasing the temperature will favor forward reaction and more CaCo3 formed.

B. More CaCo3 will be formed.

C. CaCo3 will decrease and more react ants formed.

D. Less CaCo3 will be formed.

E. Iridium is a catalyst so there is no effect

Explanation:

A. Temperature will increase because it's an endothermic reaction.

B. Adding Cao will favor forward reaction and more CaCo3 formed.

C. Removing methane, more react ants are formed and CaCo3 decreases.

D. Irridi is a catalyst so it has no effect on the CaCo3 but only speeds its rate of reaction.

3 0

2 years ago

Help pls , question is in picture

Nata [24]

Explanation:

IM PRETTY SURE IT IS D !! IF ITS WRONG IM SORRY THAT WHAT

I GOT

8 0

3 years ago

Read 2 more answers

74. Which two temperatures are identical for the same substance?

AURORKA [14]

Answer:

(A) melting point, freezing point.

Explanation:

For the same substance: when matter is transitioning from solid to liquid (melting) or liquid to solid (freezing), its temperature is fixed at the melting/freezing point, which is the same temperature.

4 0

3 years ago

Determine the number of unpaired electrons in Ca?

serg [7]

When an electron occupies an orbital of an atom singly, rather than an electron pair such electron is said to be an unpaired electron. Each atomic orbital of an atom specified by quantum numbers can contain a maximum of two electrons having opposite spins, electron pair.

The numbers of unpaired electrons are determined by the electronic configuration of an atom. The electronic configuration of calcium, $Ca$ is:

$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}$ or $[Ar]4s^{2}$

Since, from the electronic configuration it is clear that the number of electrons in valence orbital that is $4s$ is 2 that means the electrons are paired up in the valence orbital so, there are no unpaired electrons present in $Ca$ .

Hence, the number of unpaired electrons in $Ca$ is 0.

3 0

3 years ago

You placed 6.35 g of a mixture containing unknown amounts of BaO(s) and MgO(s) in a 3.50-L flask containing CO₂(g) at 30.0°C and

adelina 88 [10]

Mass of BaO in initial mixture = 3.50g

Explanation:

Let mass of BaO in mixture be x g

mass of MgO in mixture be (6.35 - x) g

Initially CO_2

Volume = 3.50 L

Temp = 303 K

Pressure = 750 torr = 750 / 760 atm

Applying ideal gas equation

PV = nRT

n = PV / RT

(n)_CO_2 = ((750/760)* 3.50) / 0.0821 * 303

(n)_CO_2 = 0.139 mole

Finally; mole of CO_2

n= PV /RT

((245/760) *3.5) / 303* 0.0821

(n)_CO_2 = 0.045 mole

Mole of CO_2 reacted = 0.139 - 0.045

=0.044 mole

BaO + CO_2 BaCO_3

Mgo + CO_2 MgCO_3

moles of CO_2 reacted = ( moles of BaO + moles of MgO)

moles of BaO in mixture = x / 153 mole

moles of MgO in mixture = 6.35 - x mole / 40

Equating,

x/ 153 +6.35/40 = 0.094

= x/153 + 6.35 / 40 - x/40 =0.094

= x (1/40 - 1153) = (6.35/40 - 0.094)

= x * 10.018464

= 0.06475

mass of BaO in mixture = 3.50g

5 0

2 years ago