9514 1404 393
Answer:
see attached
Step-by-step explanation:
You have a graph of the function ...
y = 3 +4x -x^2
You want to find solutions to the equation ...
0 = -1 +9/2x -x^2
This second equation can be made equivalent to ...
3 +4x -x^2 = p
for some suitable function p.
We can find that function using the relation ...
(3 +4x -x^2) -p = 0 = -1 +9/2x -x^2
Solving for p, we get ...
(3 +4x -x^2) -(-1 +9/2x -x^2) = p
3 +4x -x^2 +1 -9/2x +x^2 = p . . . . . . . eliminate parentheses
4 -1/2x = p . . . . . . . . . . . . . . . . . . simplify
The line we want is ...
p = -1/2x +4 . . . . . . . line with y-intercept 4 and slope -1/2
Where this line crosses the graph you have, the x-coordinates are the solutions of the equation -1 +9/2x -x^2 = 0.