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GuDViN [60]
2 years ago
11

Carolyn selected a tile randomly from the set shown below. What is the probability that she selected a while

Mathematics
1 answer:
Ratling [72]2 years ago
4 0
Letter c
Letter c
Letter c
Letter c
Letter c
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The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
A rectangular lawn 70m by 50m has two cross roads each 6m wide running in the
ser-zykov [4K]
Area of road =70*50=3500
3500*2=7000 because it has cross road
6*6=36
7000-36=6964
6964*5.50=38302
6 0
2 years ago
OUCH MY BRAIN IS HURTING AFTER TRYING TO SOLVE THIS QUESTION
maria [59]
300° CCW is the same as 60° CW. N will show up where H is now.

The 3rd selection is appropriate.
4 0
3 years ago
I need help with equation number 6
Leona [35]
Combine like terms
-2x-4=-2x-4

Since the equations are the same, the answer is infinitely many solutions.
8 0
3 years ago
PLEASE HELP ASAP DUE AT 11:59!!!!
liberstina [14]

Answer:

Uh oh- im late oof- good luck hope you figured it out

Step-by-step explanation:

4 0
2 years ago
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