3x + y = 8. -x - 2y = -10
1 answer:
Assumin we solving for the intersection or solution
elimination, ya
eliminate y's
multiply firs equation by 2 and add to 2nd
we get
6x+2y=16
<u>-x-2y=-10 +</u>
5x+0y=6
5x=6
divide both sides by 5
x=6/5
sub back
-x-2y=-10
-6/5-2y=-10
times both sides by 5
-6-10y=-50
add 6 to both sides
-10y=-44
divide both sides by -10
y=44/10
y=22/5
(x,y)
or
(1.2,4.4)
elimination, ya
eliminate y's
multiply firs equation by 2 and add to 2nd
we get
6x+2y=16
<u>-x-2y=-10 +</u>
5x+0y=6
5x=6
divide both sides by 5
x=6/5
sub back
-x-2y=-10
-6/5-2y=-10
times both sides by 5
-6-10y=-50
add 6 to both sides
-10y=-44
divide both sides by -10
y=44/10
y=22/5
(x,y)
or
(1.2,4.4)
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Answer:
80,00
Step-by-step explanation:
According to my research, the formula for the Area of a rectangle is the following,
Where
- A is the Area
- L is the length
- W is the width
Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>
800 / 2 = 400ft
So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.
400/2 = 200 ft
Now we can calculate the maximum Area using the values above.
So the Maximum area we are able to create with 800 ft of fencing is 80,00
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