Answer:
4.08 × 10⁻³
Explanation:
Step 1: Write the balanced reaction at equilibrium
NH₄I(s) ⇄ NH₃(g) + HI(g)
Step 2: Calculate the equilibrium constant
The equilibrium constant (K) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. Only gases and aqueous species are included.
![K = [NH_3] \times [HI] = 4.34 \times 10^{-2} \times 9.39 \times 10^{-2} = 4.08 \times 10^{-3}](https://tex.z-dn.net/?f=K%20%3D%20%5BNH_3%5D%20%5Ctimes%20%5BHI%5D%20%3D%204.34%20%5Ctimes%2010%5E%7B-2%7D%20%20%5Ctimes%209.39%20%5Ctimes%2010%5E%7B-2%7D%20%3D%204.08%20%5Ctimes%2010%5E%7B-3%7D)
Answer:
Here's what I get
Explanation:
Ethylamine has an N atom with a lone pair of electrons.
It can act as a Brønsted-Lowry base and accept a proton from water and become an ethylammonium ion.
The structure of the ion is shown below (there is a C atom at each of the four-way bond intersections).
An oxidation-reduction (redox<span>) </span>reaction<span> is a type of chemical </span>reaction<span> that involves a transfer of electrons between two species. An oxidation-reduction </span>reaction<span> is any chemical </span>reaction<span> in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.</span>
The element that has a complete valence electron shell is argon (Ar) since it is a noble gas in the last group on the periodic table.
Answer: 8.0 moles
Explanation:
0.6661 moles×12 H≈8.0 moles
