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Daniel [21]
3 years ago
8

What is insight learning?

Chemistry
1 answer:
krok68 [10]3 years ago
8 0
Insight learning is a type of learning or problem solving that happens all-of-a-sudden through understanding the relationships of various parts of a problem rather than through trial and error. 3. Wolfgang Kohler and his contribution to Insightful Learning
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A student sets up the following equation to convert a measurement. The (?) Stands for a number the student is going to calculate
Vika [28.1K]

Answer:

\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 3.0 \times 10^{-7} \text{ m}^{3}  

Explanation:

0.030 cm³ × ? = x m³

You want to convert cubic centimetres to cubic metres, so you multiply the cubic centimetres by a conversion factor.

For example, you know that centi means "× 10⁻²", so  

1 cm = 10⁻² m

If we divide each side by 1 cm, we get 1 = (10⁻² m/1 cm).

If we divide each side by 10⁻² m, we get (1 cm/10⁻² m) = 1.

So, we can use either (10⁻² m/1 cm) or (1 cm/10⁻² m) as a conversion factor, because each fraction equals one.

We choose the former because it has the desired units on top.

The "cm" is cubed, so we must cube the conversion factor.

The calculation becomes

\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 0.30 \times 10^{-6}\text{ m}^{3} = \mathbf{3.0 \times 10^{-7}} \textbf{ m}^{\mathbf{3}}\\\\\textbf{0.30 cm}^{\mathbf{3}} \times \left (\dfrac{\mathbf{10^{-2}}\textbf{ m}}{\textbf{1 cm}}\right )^{\mathbf{3}} = \mathbf{3.0 \times 10^{-7}} \textbf{ m}^{\mathbf{3}}

7 0
3 years ago
You are given a cube of pure copper when you calculate the density using
lara [203]

Answer:

2.01% to the nearest hundredth.

Explanation:

Percent error =[ (8.96-8.78) / 8.96]* 100

= 0.020089 * 100

= 2.0089 %

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Carbon hexafluroide formula
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The formula for Hexafluoride is F6S.

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What kind of elements do not give, receive or share electrons?
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The group of elements on the periodic table that does not participate in chemical bonding at all would be the noble gas elements. These either do not give, receive, and or share electrons.
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What are the products of photosystems ii and i in noncyclic electron flow? how is atp produced in chloroplasts?
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Oxygen and sugar (energy).
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