The image for this is attached for reference. This problem can be used by the Pythagorean equation. To make solving convenient, let us see only one part of the tent. Hence, one side is half of the tend width which is 16/2ft. Height is 12 ft. The unknown side is the hypotenuse. The answer is:
Answer:
Step-by-step explanation:
On a grid,
go to the middle, aka 0,0
move left 4 times, but stay on the same line. Then draw that line up and down on the -4 of x.
sorry if this isn't clear
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
Answer:
-12
Step-by-step explanation:
(-2)(-3)^2-2(2-5). Original
-2(9)-2(2-5) Distribute Exponents
-18-4+10 Distribute Parentheses
-22+10 Do subtraction
-12 Do Addition
Answer:
2520 gallons
Step-by-step explanation:
3000 gallons -780 gallons drained over 6 hours then add 300 gallons over three hours = 2520 gallons
