The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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brainly.com/question/25829061
Answer:
5
Step-by-step explanation:
Answer:
53.13
Step-by-step explanation:
ANSWER If you solve for x you get -4/3 y+5/6 If you solve for y you get -3/4x +5/8.
Step-by-step explanation
and then the second answer is
If you solve for x you get-4/3y +-1/2
If you solve for y you get -3/4x +-1/2
Answer:
Step-by-step explanation:
2 - Corresponding angles theorem
6 - Alternate exterior angles theorem
8 - Transitive Property
