For this problem,we use the Fundamental Counting Principle. You know that there are 7 digits in a number. In this principle, you have to multiply the possible numbers for every digit. If the first number cannot be zero, then there are 9 possible numbers. So, the value for the first digit is 9. The second digit could be any number but less of 1 because it was used in the 1st digit. So, that would be 10 - 1 = 9. The third digit must be the value in the second digit less than 1. That would be 9 - 1 = 8. And so on and so forth. The solution would be:
9×9×8×7×6×5×4 = 544,320 7-digit numbers
To use the elimination method, you have to create variables that have the same coefficient, then you can eliminate them.
167+57 written in base ten method
Answer:
7
Step-by-step explanation:
n! Might be 7, and n might be 6. r might also be 6. So 6 - 6= 0! = 1
So I think it might be 7 ÷ 1, which is 7.
