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OLga [1]
2 years ago
10

The charge in dollars for cab rides in one

Mathematics
1 answer:
Sergeeva-Olga [200]2 years ago
6 0
F(3) = $4 + $2.5(3)
f(3) = $4 + $7.5
f(3) = $11.50
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What fraction is considered undefined?​
AysviL [449]

Answer:

when 0 on the bottom is zero

Step-by-step explanation:

that mean there would be no whole nor a proper quotient

6 0
2 years ago
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Danny brought a car for £10000 the value of the car depreciated by 20% in the first year then the value of the car depreciated b
Levart [38]

£7200

In first year depreciates by 20%, that is it is worth 80% of it's original value

80% = \frac{80}{100} = 0.8

value after 1 year = 0.8 × £10000 = £8000

In the second year it depreciates by 10% of it's value, that is it is worth 90% of it's value at the end of the first year.

90% = \frac{90}{100} = 0.9

value after 2 years = 0.9 × £8000 = £7200


6 0
3 years ago
you are buying wood to build a gate for your backyard. if your car trunk has the following dimensions (47 inches by 33 inches by
riadik2000 [5.3K]

The longest piece of wood that could fit in your trunk to build a gate for the backyard is 60.65 inches.

<h3>How to measure diagonal of the cuboid?</h3>

The length of the diagonal of the cuboid is found out using the following formula.

D=\sqrt{l^2+b^2+h^2}

Here, (l) is the length of the cuboid, (w) is the width, and (h) is the height of the cuboid.

The wood has to buy to build a gate for backyard. The car trunk has the following dimensions (47 inches by 33 inches by 19.5 inches). Here, we have,

  • Length (l)=47 in
  • Width (w)=33 in
  • Height (h)=19.5 in

The longest piece of wood which fits is equal to the length of diagonal of cuboid. Put the values in the formula,

D=\sqrt{47^2+33^2+19.5^2}\\D=\sqrt{3678.25}\\D=60.65\rm\; in

Thus, the longest piece of wood that could fit in your trunk to build a gate for the backyard is 60.65 inches.

Learn more about the cuboid here;

brainly.com/question/22694657

#SPJ1

3 0
2 years ago
I only have 2 hours to do this can someone plz help
wolverine [178]
Figure it out tonta tonta
8 0
3 years ago
The lengths of the diagonals of a rhombus are 2x and 10x. What expression gives the perimeter of the rhombus?
True [87]

Answer:

P=4x\sqrt{26}\ units

Step-by-step explanation:

we know that

The sides of a rhombus are all congruent and the diagonals are perpendicular bisectors of each other

so

Applying the Pythagorean Theorem

c^2=a^2+b^2

where

c is the length side of the rhombus      

a and b are the semi-diagonals

we have

a=2x/2=x\ units\\b=10x/2=5x\ units

substitute the values

c^2=x^2+(5x)^2

c^2=26x^2

c=x\sqrt{26}\ units

To find out the perimeter of the rhombus multiply the length side by 4

P=(4)(x\sqrt{26})

P=4x\sqrt{26}\ units

6 0
3 years ago
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