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Len [333]
3 years ago
15

85. A 1500 kg car accelerates forward due to an applied force of 25001 while experiencing 175 N of friction a. What is the magni

tude of the weight of the car? b. What is the magnitude of the force that causes the acceleration? c. What is the acceleration of the car?​
Physics
1 answer:
klio [65]3 years ago
6 0

Answer:

See answers below

Explanation:

a.

F = mg,

F = (1500 kg)(9.8 m/s²) = 14,700 N

b.

2500 N - 175 N = 2325 N

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When you pedal a bicycle, maximum torque is produced when the pedal sprocket arms are in the horizontal position, and no torque
poizon [28]

Answer:

This is because when the pedal sprocket arms are in the horizontal position, it is perpendicular to the applied force, and the angle between the applied force and the pedal sprocket arms is 90⁰.  

Also, when the pedal sprocket arms are in the vertical position, it is parallel to the applied force, and the angle between the applied force and the pedal sprocket arms is 0⁰.

Explanation:

τ = r×F×sinθ

where;

τ is the torque produced

r is the radius of the pedal sprocket arms

F is the applied force

θ is the angle between the applied force and the pedal sprocket arms

Maximum torque depends on the value of θ,

when the pedal sprocket arms are in the horizontal position, it is perpendicular to the applied force, and the angle between the applied force and the pedal sprocket arms is 90⁰.

τ = r×F×sin90⁰ = τ = r×F(1) = Fr (maximum value of torque)

Also, when the pedal sprocket arms are in the vertical position, it is parallel to the applied force, and the angle between the applied force and the pedal sprocket arms is 0⁰.

τ = r×F×sin0⁰ = τ = r×F(0) = 0 (torque is zero).

4 0
4 years ago
How much force (in Newtons) is needed to accelerate a 160 kg object at a rate of 4 m/s2?
Klio2033 [76]

Answer:

C. 640

Explanation:

The minimum force would occur in a frictionless environment and act parallel to any abutting surface.

F = ma = 160(4) = 640 N

3 0
3 years ago
In simple harmonic motion, the magnitude
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Answer:

2. displacement is maximum

Explanation:

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\sf \huge \red{Answer : - }

Ratio of resistances of two bulbs = 2:3

Both are connected in series.

We have to find the ratio of powers in the bulbs..

We know that, current flow through each conductor in series connection remains same. So, we have to use that formula of power which shows relation between current and resistance.

  • P = I² × R

For series connection; P ∝ R

→ P₁/P₂ = R₁/R₂

→ P₁/P₂ = 2/3

→ P₁ : P₂ = 2 : 3

3 0
4 years ago
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