D. What is the net force on the bowling ball rolling lane
1 answer:
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Answer:
Explanation:
In order to solve this question, we would need to incorporate Stoichiometry, which involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.
Here's a balanced equation for the reaction:
Let us define work as;
where
External pressure is given as , therefore the work solely depends on the change in volume and since the reactants are solids, none of the reactants contribute to the volume. Hence,
To find the volume of the products, we need to first find the amount of moles of the product made from using the molar mass of
which is 101.1032 g/mol
Now let us convert moles of into moles of
and
using the stoichiometric ratios from our balanced equation of the reaction.
is not factored into the volume calculation because it is a solid.
Now let us also convert the moles of and
into grams using their respective molar masses.
We will now proceed to convert grams into volume using the density values provided.
Summing up the two volumes, we get the final volume
Plugging everything into the equation, we get:
Finally, let us convert into joules using the conversion rate of;
Answer:
Tension, T = 2038.09 N
Explanation:
Given that,
Frequency of the lowest note on a grand piano, f = 27.5 Hz
Length of the string, l = 2 m
Mass of the string, m = 440 g = 0.44 kg
Length of the vibrating section of the string is, L = 1.75 m
The frequency of the vibrating string in terms of tension is given by :
T = 2038.09 N
So, the tension in the string is 2038.09 N. Hence, this is the required solution.
Here,
m=80 kg
R= 6.4*10^6 m
and t=24*3600=86400 s
Centripetal acceleration:
a=ω²r
=(2
/86400)^2 * 6.4*10^6
=0.034 m/s²
m=80 kg
R= 6.4*10^6 m
and t=24*3600=86400 s
Centripetal acceleration:
a=ω²r
=(2
=0.034 m/s²