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nexus9112 [7]
4 years ago
11

The builders of the pyramids used a long ramp to lift 20000-kg (20.0-ton) blocks. If a block rose 0.840 m in height while travel

ing 20.0 m along the ramp surface, how much uphill force was needed to push it up the ramp at constant velocity

Physics
1 answer:
olga_2 [115]4 years ago
8 0

Given Information:  

Mass = m =  20000 kg

Height of ramp = h = 0.840 m

Length of ramp = L = 20 m

Required Information:  

Uphill Force = F = ?

Answer:

F = 8232 N

Explanation:

The force can be found using the equation

F = mgsinθ

Where m is the mass of block, g is the acceleration due to gravity

Since the ramp can be modeled as an inclined plane so it can formed into a triangle, recall that in right angle triangle sinθ is equal to opposite over hypotenuse. The opposite is the height and hypotenuse is the ramp surface.

sinθ = h/L = 0.840/20 = 0.042

F = 20000*9.8*0.042

F = 8232 N

Therefore, an uphill force of 8232 N would be needed.

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3 years ago
Which of the following is a common human relations mistake?
Dafna11 [192]
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3 years ago
A heat-conducting rod consists of an aluminum section, 0.30 m long, and a copper section, .70m long. Both sections have a cross-
Igoryamba
Thermal conductions
K= QL/ART
Aluminium T₁ = 10 + 273.15
                    T₂ = 283.15k
205 = 2.0  × 0.30/4× 10⁻⁴ × (T₂ - 283.15)
Copper
385 = Q × 0.70/4×10⁻⁴ ×(433.15 - T₂)
Where T₃ = 160 + 273.15
T₃ = 433.15K
From 2 to 3
205/385 = 0.30/0.70 × 433.15 - T₂/T₂ - 283.15
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3 years ago
Please i need detailed explanation​
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Answer:

2Micro Farahds

Explanation:

Its in the picture.

I Hope it helps.

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