Answer:
Increases
Explanation:
Since power P=IV
Then it means when current increases, the power increases hence brightness increases. I represent current, P is power and v is voltage.
Current of capacitor when in series connection is given by
where I is current across capacitor, f is frequency, C is capacitance and v is voltage across capacitance. From this second formula, it is evident that an increase in capacitance increases the current across the capacitor. Therefore, if current increases, power also increases leading to an increase in brightness
I think it’s, its direction would reinforce the original movement
Would be A 1012 N/C because The magnitude of the electric field at distance r from a point charge q is E=k
e
q/r
2
, so
E=
(5.11×10
−11
m)
2
(8.99×10
9
N.m
2
/C
2
)(1.60×10
−19
C)
=5.51×10
11
N/C∼10
1
2N/C
making (e) the best choice for this question.
Let us assume that the definition of frequency, wavelength and wave speed is determined by the function
Here,
v = Velocity of wave
= Wavelength
f = Frequency
We know that the earth has the ability to absorb visible light but that it can also emit a longer radiation wavelength. This assessment allows us to confirm that option A. Is correct. In turn, if said wavelength is large, being inversely proportional to the frequency,
This does tend to be lower radiation. The correct options are:
A.The earth absorbs visible light and emits radiation with a longer wavelength.
B.The earth absorbs visible light and emits radiation with a lower frequency.
