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Mashutka [201]
3 years ago
6

What is the sum of 2 and 3

Mathematics
2 answers:
dalvyx [7]3 years ago
5 0
2 + 3 is 5.
Think of it like this:
If you have two candies, then are given three more candies, then count them all up, you will realize that you have 5 candies.
Shkiper50 [21]3 years ago
4 0
6. Hope this hellpppp.
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3 years ago
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Neil put on a blindfold and picked 72 jelly beans from a jar.
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3 years ago
In an indoor soccer stadium, there are 20 seats in the first row and 31 seats in the second row. Every
Finger [1]
<h3>________________________________________________</h3>

Step-by-step Solution for Part-a:

<u>We know that:</u>

  • Row-1: 20 seats
  • Row-2: 20 + 11
  • Row-x: 20 + (11x - 11)

Since the number of rows in rows x is 20 + (11x - 11), the formula to calculate the number of seats in each row is 20 + (11x - 11).

<h3>________________________________________________</h3>

Step-by-step Solution for Part-b:

<u>We know that:</u>

  • y rows = 174 seats
  • Obtained rule from part-a: 20 + (11y - 11)

<u>Solution:</u>

  • 20 + (11y - 11) = 174 rows
  • => 20 + 11y - 11 = 174 rows
  • => 9 + 11y = 174 rows
  • => 11y = 174 - 9 rows
  • => 11y = 165
  • => y = 165/11
  • => y = 15

Hence, the row which has 174 seats is row 15.

<h3>________________________________________________</h3>
5 0
2 years ago
Create a matrix for this system of linear equations, The determinant of the coefficient matrix is
marin [14]

Answer:  The determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

Step-by-step explanation:  The given system of linear equations is :

2x+y+3z=13~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\x+2y=11~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\3x+z=10~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

We are given to find the determinant of the coefficient matrix and to find the values of x, y and z.

The determinant of the co-efficient matrix is given by

D=\begin{vmatrix}2 & 1 & 3\\ 1 & 2 & 0\\ 3 & 0 & 1\end{vmatrix}=2(2-0)+1(0-1)+3(0-6)=4-1-18=-15.

Now, from equations (ii) and (iii), we have

x+2y=11~~~~~\Rightarrow y=\dfrac{11-x}{2}~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)\\\\\\3x+z=10~~~~~~\Rightarrow z=10-3x~~~~~~~~~~~~~~~~~~~~~~~~~(v)

Substituting the value of y and z from equations (iv) and (v) in equation (i), we get

2x+y+3z=13\\\\\Rightarrow 2x+\dfrac{11-x}{2}+3(10-3x)=13\\\\\Rightarrow 4x+11-x+60-18x=26\\\\\Rightarrow -15x+71=26\\\\\Rightarrow -15x=26-71\\\\\Rightarrow -15x=-45\\\\\Rightarrow x=3.

From equations (iv) and (v), we get

y=\dfrac{11-3}{2}=4,\\\\z=10-3\times3=1.

Thus, the determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

3 0
3 years ago
Simplify........................​
Ivahew [28]

Answer:

\frac {x^{3}-4x^{2}-20x+32}{x^{3}+2x^{2}-4x-8}

Step-by-step explanation:

make the denominator same

\frac{(x^{2}-4)(x-2)}{(x^{2}-4)(x+2) }-\frac{(2x+20)(x+2)}{(x^{2}-4)(x+2)}

then expand

\frac {x^{3}-2x^{2}-4x+8}{x^{3}+2x^{2}-4x-8} - \frac {2x^{2}+24x+40}{x^{3}+2x^{2}-4x-8}

join

\frac {x^{3}-4x^{2}-20x+32}{x^{3}+2x^{2}-4x-8}

i think but not sure

3 0
3 years ago
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