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3 years ago

8

If f(x) = x^3, which of the following describes the graph of f(x + 2)?

2 answers:

AleksAgata [21]3 years ago

6 0

This problem is trying to be confusing on purpose the way its written, so ill do my best to explain. f(x+2) is a silly way of saying that your equation is translates up two units, the "+2" is again "b" in the equation y=mx+b
so its telling you to basically write your equation as y=x^3+2. they will also try to confuse you by showing you this,
y=(x+2)^3, which is a horizontal translation, twice to the left, so don't be fooled. all in all with your final equation as y=x^3+2, you are left with a vertical translation upwards of 2 : )

slava [35]3 years ago

4 0

Answer:

The answer is A on Edge

Step-by-step explanation:

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As Saturn revolves around the sun, it travels at a rate of approximately 6 miles per second. Convert this rate to miles per minu

Digiron [165]

360 miles per minute 1440 miles in 4 minutes. :)

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4 years ago

5x-4y > 10<br> 3x-2y < -7

Dafna11 [192]

Answer:

$x > \frac{2(5 + 2y)}{5} \\ \\ x < \frac{2y - 7}{3}$

Step-by-step explanation:

$1. \: 5x > 10 + 4y \\ 2. \: x > \frac{10 + 4y}{5} \\ 3. \: x > \frac{2(5 + 2y)}{5} \\ \\ \\ 1. \: 3x < - 7 + 2y \\ 2. \: 3x < 2y - 7 \\ 3. \: x < \frac{2y - 7}{3}$

6 0

1 year ago

Write the polynomial equation for -1/5,-1/2,-4

ycow [4]

Answer:

(5x+1)(2x+1)(x+4)

Step-by-step explanation:

The factored from of a polynomial can be found from the zeros or x-intercepts of the graph.

The x-intercepts here are x= -1/5, x=-1/2 and x= -4. You can find the factors by finding the expression which solves for each value.

Since x = -1/5 then the factor is 5x+1.

Since x = -1/2 then the factor is 2x+1.

Since x = -4 then the factor is x+4.

So the factored form is (5x+1)(2x+1)(x+4).

5 0

3 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

3 years ago

Which point represents an approximate solution to this system of equations?

joja [24]

The answer is D. (2.9,-22.8)

5 0

3 years ago

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