Since s(t) is the position, we can take the derivative to get the equation for the velocity.
i did that and got this but the answer is not correct:s(t)=2t 3 −24t 2 +90t v(t)=s ′ (t)=6t 2 −48t+90=6(t−3)(t−5) a(t)=s ′′ (t)=12t−48=12(t−4)
(A) forward 0<t<3 or t>5, backward 3<t<5(B) speeding up t>4, slowing down 0<t<4
Actually, I need to correct that.
Forward is [0,3) union (5,infinity)slowing down is [0,4) and speeding up is (4,infinity)
The answer is 82 because 5+7=12 then 3+4=7 plus the 1 = 82
Hello,
I think the answer is B.
Hope this helps!!
Brainliest?
So first you move the b over: x/c=y-b. Then you divide y-b by c.
x = (y-b)/c
To write the coefficients of the 8 terms, either start with a combination of 7 things taken 0 at a time and continue to 7 things taken 7 at a time or use the 7th row of Pascal’s triangle.
For the first term, write x to the 7th power and 3 to the 0 power. Then decrease the power on x and increase the power on y until you reach x to the 0 and y to the 7.
Simplify by evaluating the coefficients and powers of 3.