1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
torisob [31]
3 years ago
12

Can you help me on this. It is due today

Mathematics
1 answer:
seraphim [82]3 years ago
4 0

The amount after 6 years is $3906.18

Step-by-step explanation:

Step 1 :

Given,

Principal  = $3500

number of years = 6

Rate of interest = 1.83% compounded daily

We need to determine the amount

Step 2 :

The amount can be computed using the formula

A = P (1 + \frac{r}{100} )^{n}

where P represents the principal amount

r = interest rate

n = number of terms.

Here, interest = 1.83% daily = 1.83 ÷ (100× 365)

n = 6 × 365 (because interest given is compounded daily)

Hence A = 3500 ( (1 + \frac{1.83}{365 * 100 } )^{6 * 365})  =  $3906.18

Step 3 :

Answer :

The amount after 6 years is $3906.18

You might be interested in
What is the answer to both of these?
Law Incorporation [45]

Answer:

The answer for 24 is B, so its 7.50

3 0
3 years ago
Round 428,213 to the nearest ten thousand
givi [52]

Answer:

Round 428,213 to the nearest ten thousand = 428,210




6 0
3 years ago
line segment AB has endpoints A (7.5,4.2) and B (2.3,5.4). Find the coordinates of the point that divides the line segment direc
Marrrta [24]

9514 1404 393

Answer:

  (6.2, 4.5)

Step-by-step explanation:

We want, for some point P, ...

  (P -A) / (B -P) = 1 / 3

  3(P -A) = (B - P) . . . . . multiply by 3

  4P = B +3A . . . . . . . . add P+3A

  P = (B +3A)/4 . . . . . . .divide by 4

Filling in the coordinate values, we can find P to be ...

  P = ((2.3, 5.4) +3(7.5, 4.2))/4 = (2.3+22.5, 5.4+12.6)/4

  P = (6.2, 4.5)

5 0
3 years ago
When h is one-half and j is one-third, g is 4. if g varies jointly with h and j, what is the value of g when h is 2 and j is 3?
Softa [21]
I don’t know the answer to this question
3 0
2 years ago
Read 2 more answers
state whether the lines represented by the equations y=1/2x-1 and y+4=-1/2(x-2) are paraller, perdendicular, or neither
Brrunno [24]
The easiest way to tell whether lines are parallel, perpendicular, or neither is when they are written in slope-intercept form or y = mx + b. We will begin by putting both of our equations into this format.

The first equation, y =  \frac{1}{2}x - 1 is already in slope intercept form. The slope is 1/2 and the y-intercept is -1.

The second equation requires rearranging.
y + 4 =  -\frac{1}{2}(x - 2) \\ y + 4 = -\frac{1}{2}x + 1 \\ y = - \frac{1}{2} x- 3
From this equation, we can see that the slope is -1/2 and the y-intercept is -3.

When lines are parallel, they have the same slope. This is not the case with these lines because one has slope of 1/2 and the other has slope of -1/2. Since these are not the same our lines are not parallel.

When lines are perpendicular, the slope of one is the negative reciprocal of the other. That is, if one had slope 2, the other would have slope -1/2. This also is not the case in this problem.

Thus, we conclude that the lines are neither parallel nor perpendicular.
8 0
4 years ago
Other questions:
  • I dont understand what does this want me to do?
    13·1 answer
  • A middle school has a speech club with a total of 18 students. The ratio of girls to boys is 4:5. How many girls are in the spee
    7·1 answer
  • aA shopkeeper Sold His goods for rupees 16950 25 discount and then 13 % sales tax. find the amount of discount ?​
    6·2 answers
  • 10 feet and 3 inches = inches
    5·1 answer
  • What is the slope of the line? x+3y=100
    10·1 answer
  • If a:b is 2:5 and b:c is 3:4, find a:b:c
    6·1 answer
  • HELP PLEASE!!!!
    13·1 answer
  • What is the area of triangles in square yards
    5·1 answer
  • Just answer number 5 pls
    10·1 answer
  • Use (x-3)^2 -6<br> to solve x^2-6x+3=0 <br> leave your answer in surd form
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!