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mart [117]
3 years ago
10

6. What are the zeros for the function b(t) = (t -5) (t+3) (t-2)?

Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

b(t) = (t -5) (t+3) (t-2)

zero of the function is given by

b(t) = (t -5) (t+3) (t-2)=0

such that

(t -5) (t+3) (t-2)=0

i.e.,  (t -5)=0 and   (t+3) =0  and   (t-2)=0

consider (t -5)=0

                t -5 =0

                t+5-5=0+5

                t=5

consider (t +3)=0

                t +3 =0

                t+3-3=0-3

                t= -3

consider (t -2)=0

                t -2 =0

                t+2-2=0+2

                t=2

answer is B

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given that by using the distributive property to match the given equivalent expressions.

1) Given expression is -7(-4+x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

-7(-4+x) =(-7)(-4)+(-7)(x)

=28-7x

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2) Given expression is -7(4-x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

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3) Given expression is 7(4+x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

7(4+x) =(7)(4)+(7)(x)

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<h3>By Distributive property a(b+c)=ab+ac</h3>

7(-4-x) =(7)(-4)+(7)(-x)

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Hence the matched equivalent expressions are

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Step-by-step explanation:

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