Ask question

Ask question

All categories

2 years ago

11

I NEED HELP NOW...........NO LINKS AND TROLLING PLS

1 answer:

Troyanec [42]2 years ago

6 0

Answer:

that's similar to what have but its D

You might be interested in

Help me find x. I will mark the best explination the brainliest. Just PLEASE I need help.

Hatshy [7]

x makes a linear pair with 120 degrees, so is supplementary:

Answer: 60 degrees

3 0

3 years ago

What is the nth term?

kumpel [21]

Let $a_k$ denote the <em>k</em>th term of the sequence. Then

$a_k=a_1+d(k-1)$

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

$S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n$

From the formula for $a_k$ , we get

$S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)$

$S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k$

$S_n=na_1+\dfrac{d(n-1)n}2$

$S_n=\dfrac n2(2a_1-d+dn)$

So we have $d=-5$ , and $2a_1-d=16$ so that $a_1=\frac{11}2$ .

Then the <em>n</em>th term in the sequence is

$a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}$

7 0

3 years ago

What is the distance between the points (2, 1) and (14, 6) on a coordinate<br> plane?

Black_prince [1.1K]

Answer:

d = 13 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (2, 1 ) and (x₂, y₂ ) = (14, 6 )

d = $\sqrt{(14-2)^2+(6-1)^2}$

= $\sqrt{12^2+5^2}$

= $\sqrt{144+25}$

= $\sqrt{169}$

= 13

8 0

2 years ago

Read 2 more answers

If (fog)(x)=7x-1/3 and f(x)=3x+5,find g(x),where g(x)is linear<br>

Svetach [21]

Answer: $g(x) = \dfrac73x-\dfrac{16}{9}$

Step-by-step explanation:

Given: $(fog)(x)=7x-\dfrac13$

$f(x)=3x+5$

and g(x) is linear.

A linear function is of the form : $y= mx+c$

Let $g(x)= mx+c$

Then, $(fog)(x)=f(g(x))= f(mx+c)$

$= 3(mx+c)+5\\\\=3mx+3c+5$

Comparing it with the original (fog)(x), we get

$3mx+3c+5=7x-\dfrac{1}{3}$

Comparing coefficient of x and constants separately

$3m=7,\ \ \ \ 3c+5=-\dfrac13\\\\\Rightarrow\ m=\dfrac{7}{3},\ \ \ \ 3c =-\dfrac{1}{3}-5\\\\\Rightarrow\ m=\dfrac{7}{3},\ \ \ \ 3c =-\dfrac{16}{3}\\\\\Rightarrow\ m=\dfrac{7}{3},\ \ \ \ c =-\dfrac{16}{9}$

So, $g(x) = \dfrac73x-\dfrac{16}{9}$

3 0

4 years ago

Geometry question, please help!

Gennadij [26K]

What is the question???????

7 0

3 years ago

Read 2 more answers