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astra-53 [7]
3 years ago
8

Evaluate 11+(−7*7)−9.

Mathematics
1 answer:
Butoxors [25]3 years ago
6 0

Answer:

-47

Step-by-step explanation: Remember p.e.m.d.a.s

so start with (-7*7) = -49

then add so 11 + -49 = -38

then subtract so  -38 - 9 = -47

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please help me with this math problem, the question is on the picture that i attached, ill mark brainliest if the answer is corr
dsp73

Answer:

cos z = 35 / 37

Step-by-step explanation:

cos z is the ratio of the adjacent side of a triangle (the side adjacent to angle z to the hypotenuse:

cos z = (adj. side) / (hypotenuse)

Here we have cos z = 35 / 37

7 0
3 years ago
Patricia invites her friends to dinner at a restraint. The bill is $32.80 she decides to leave a 15% tip. If she pays with a $50
kobusy [5.1K]

Answer:

First you will want to turn 15% into a decimal, then you will subtract the decimal from 50. Hope this helped

Step-by-step explanation:

8 0
3 years ago
What is the percentage of 15 out of 75
Archy [21]

 \frac{15}{75}= \frac{3}{15}= \frac{1}{5}= \frac{20}{100}



The answer is 20%


4 0
3 years ago
Read 2 more answers
M&lt;2 = 4x - 26,<br> m&lt;3 = 3x + 4
mestny [16]

Answer:

m<2 = 4x - 26 = 4(30) - 26 = 94 degrees

m<3 = 3x + 4 = 3(30) + 4 = 94 degrees

Step-by-step explanation:

Congruent angles are equal, so m<2 = m<3

4x - 26 = 3x + 4

x = 30

m<2 = 4x - 26 = 4(30) - 26 = 94 degrees

m<3 = 3x + 4 = 3(30) + 4 = 94 degrees

8 0
3 years ago
A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}

The information provided is:

<em>x</em> = number of students who responded as"yes" = 70

<em>n</em> = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

p=\frac{x}{n}

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0
3 years ago
Read 2 more answers
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