Answer:
Find the midsegment of the triangle which is parallel to CA.
Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.
We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.
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Actual area of the rectangular building = 5040 feet²
Step-by-step explanation:
Length of the rectangular building = 7 feet
Width of the rectangular building = 5 feet
Now, The building is made with a scale factor of 12
So, Actual length of the rectangular building = 84 feet
Actual width of the rectangular building = 60 feet
Now, Actual area of the rectangular building = Length × Width
⇒ Actual area of the rectangular building = 84 × 60
⇒ Actual area of the rectangular building = 5040 feet²
Answer:
$33
Step-by-step explanation:
C = 6(3) + 15
C = 18 + 15
C = 33
Brandy got 1162 scoring for competing in the bonus round of the particular game show.
Step-by-step explanation:
- By getting the 523 scores in the literature questions sections a 639 point in the automobile section. next could be the bonus round.
- So the score she obtained so far to compete in the bonus round is found by the addition of the two scores.
- The addition of 523 and 639 gives us 1162 which is the score for entering the bonus round.
Step-by-step explanation:
sqrt(5x)×(sqrt(8x²) - 2×sqrt(x)) =
sqrt(5x × 8x²) - 2×sqrt(5x × x) =
sqrt(40x) × x - 2x × sqrt(5) =
2x×sqrt(10x) - 2x×sqrt(5)
therefore, the last option is correct.
