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Bad White [126]
3 years ago
9

How long has it been since george washington was president?

Advanced Placement (AP)
2 answers:
aleksandrvk [35]3 years ago
8 0

Answer:

he was elected in 1789 and his presidency ended in 1797 so 224 years ago

Alex777 [14]3 years ago
8 0

Answer:

5 years

only

5years

bro

i

know

and

i

help

you

answer

is

five

year

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<span>In the BGE mirror setting, the sideview mirror is set to see the lane next to your vehicle.</span>
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3 years ago
In general, which of the following is required for a successful marriage?
lawyer [7]

Answer: The correct answer is  D.  None of the above

Explanation:

Although the first three alternatives may eventually contribute, none of them is a prerequisite for a successful marriage.

Living together before the wedding is meant to get to know each other better, but there is no indication that it will make the marriage last any longer. Likewise, religious and premarital counseling can help the couple, but without any guarantee. What makes the marriage successful is the couple's complicity, love, and tolerance for the defects they both have.

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3 years ago
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Answer:

M=0.09 mol/L

Explanation:

M=mol/volume

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M=0.09 mol/L

3 0
3 years ago
The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0
3 years ago
The March 11, 2011, earthquake in Japan caused a tsunami that crashed into the Fuushima nuclear power plant on Japan's Pacific c
Ksivusya [100]

Answer:

Following major earthquake, a 15- metre tsunami disable the power supply and cooling of three Daiichi reactors, causing a nuclear accident being on March 11, 2011. All three cords largely melted in the first three days.

Explanation:

8 0
3 years ago
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