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Mila [183]
3 years ago
14

Guys help only 2 more questions

Mathematics
2 answers:
AleksAgata [21]3 years ago
6 0

Answer:

The person who answer this before me is right it is A

Step-by-step explanation:

I hope you get a 100%

klasskru [66]3 years ago
4 0

Answer:

the option must be a or b ....

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Evaluate the related series described 4 - 12 + 36 - 108 n=6
Arada [10]

Answer:

11/54 is n did you want it in decimal form 0.2037 bar on top of 03

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3 years ago
Solve the equation: 5/6x - 10 = 1/3(x - 15)
Harlamova29_29 [7]

Answer:

X =10

Step-by-step explanation:

If you have a scientific calculator that can help you a lot.

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4 0
3 years ago
Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p
Ymorist [56]

Answer:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

A\sim Uniform(1 ,7)

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

B\sim Exp(\lambda=\frac{1}{30 min})

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

E(A +B)

Since the two random variables are assumed independent, then we have this

E(A+B) = E(A)+E(B)

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

E(A)=\frac{1+7}{2}=4 hours

The expected value for the exponential distirbution is given by :

E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx

If we use the substitution y=\lambda x we have this:

E(X)=\frac{1}{\lambda} \int_{0}^\infty y e^{-\lambda y} dy =\frac{1}{\lambda}

Where X represent the random variable and \lambda the parameter. If we apply this formula to our case we got:

E(B) =\frac{1}{\lambda}=\frac{1}{\frac{1}{30}}=30min

We can convert this into hours and we got E(B) =0.5 hours, and then we can find:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

And in order to find the variance for the random variable A+B we can find the individual variances:

Var(A)= \frac{(b-a)^2}{12}=\frac{(7-1)^2}{12}=3 hours^2

Var(B) =\frac{1}{\lambda^2}=\frac{1}{(\frac{1}{30})^2}=900 min^2 x\frac{1hr^2}{3600 min^2}=0.25 hours^2

We have the following property:

Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)

Since we have independnet variable the Cov(A,B)=0, so then:

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

3 0
3 years ago
3-5(3a+6) in standard form
Gre4nikov [31]

Answer:

3 - 15a - 30 \\  - 15a - 27

Good luck!

Intelligent Muslim,

From Uzbekistan.

6 0
3 years ago
Larry is shipping nails that weigh a total of 53 pounds. he must divide the nails equally into 4 boxes. how many nails in each b
lina2011 [118]
13 boxes and there will be 1/4 of a box left over
3 0
3 years ago
Read 2 more answers
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