Answer:
2y² + 9
---------------
15y³
Step-by-step explanation:
Start by identifying the LCD, and then change each fraction so that its denominator is the LCD.
Here the LCD is 15y³, which is evenly divisible by 15y and 5y³.
Focus now on the first fraction: 2 / (15y). Multiplying numerator and denominator of this fraction by y² results in
y²·2 2y²
--------- → ----------
y²·15y 15y³ ←This is the correct LCD
Multiplying numerator and denominator of the second fraction by 3 results in:
3·3 9
------------ → ---------
3·5y³ 15y³ ←This is the correct LCD
So now those two original terms look like:
2y² 9
--------- + --------
15y³ 15y³
and this can be written in simpler form as:
2y² + 9
---------------
15y³
If a=c and b=c then a=c this is transitive property
Answer:
A thend D
Step-by-step explanation:
5 the answer I took the test
Well, since these are rectangles, and both have 2 measurements, it would be quite simple, you must find how 9 and 15 are similar, then see if that same similarity is found within the 3 and the 5.
the answer is yes, they are similar because...
9×1 1/3=15
and
3× 1/3=5
therefore they are similar.
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