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d1i1m1o1n [39]
3 years ago
8

There are 45 vehicles in the parking lot.three fifths of the vehicles are minivans.how many of vehicles in the parking lot are m

inivans
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0
45/5=9
3*9=27 are minivans
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What is the value of x in 34 + 2x = 40
alekssr [168]

Hello from MrBillDoesMath!

Answer:

3

Discussion:

34           + 2x = 40             => subtract 34 from both sides

(34-34)   + 2x = 40 - 34     => as (34-34) = 0 and 40-34 = 6

2x                   = 6               => divide both sides by 2

x = 6/2 = 3

Check the answer:

Does 34 + 2x = 40 if x = 3 ?

Does 34 + 2(3) = 40 ?

Does 34 + 6      = 40 ?  YES! so the answer checks.

Thank you,

MrB

4 0
3 years ago
Read 2 more answers
The chemical Element ,silver , boils at temperatures of 3924°F what is the boiling point for silver in degrees Celsius ? round y
mixer [17]

Answer:

2162.2 degrees Celsius

Step-by-step explanation:

Celsius (°C) = (Fahrenheit - 32) / 1.8

3924-32 = 3892

3982 / 1.8 = 2162.2222222222222222222222

Rounded is 2162.2

8 0
2 years ago
4 × (3 + 7) = (4 ×[]) + (4 ×[])
Naily [24]

Answer:

4 × (3 + 7) = (4 ×7) + (4 × 3)

Step-by-step explanation:

If you go by the order of PEMDAS you would do the parentheses first. 3 + 7 =10. 10 × 4 = 40. Then you would just use the distributive property and do (4× 7) + (4 × 3)

4 × 7 = 28 and 4 × 3 = 12 28 +12 =40

8 0
3 years ago
Which of the following is NOT equivalent to the nxn matrix A being invertible? A. The homogeneous system associated to A has a u
storchak [24]

Answer:

Option C

Step-by-step explanation:

  • For the matrix A of order n\times n to be invertible, its determinant must not be equal to zero, |A| \neq0, A^{- 1}  exists if- AC = CA = I, where I is identity matrix.
  1. The homogeneous equation with coefficient matrix A has a unique solution:

       AB = 0, B = A^{- 1}.0 = 0

      Thus, B = (0, 0, 0......., 0) is a unique solution

     2. The non - homogeneous equation system with coefficient matrix A has  a unique solution:

For an equation- AY = D

Y = A^{- 1}.D is a unique solution

     3. Every non homogeneous equation with coefficient matrix A is not consistent as:

For an equation- AY = D, has a solution.l Thus coefficient matrix is inconsistent whereas augmented matrix is.

      4. Rank of matrix A = n, Thus the column space of A is R^{n}

      5. Since, column space of A = R^{n}, thus x→xA is one-to-one

       

5 0
3 years ago
Three students, Alicia, Benjamin, and Caleb, are constructing a square inscribed in a circle with center at point C. Alicia draw
True [87]

Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.

<h3>Inscribing a square</h3>

The steps involved in inscribing a square in a circle include;

  • A diameter of the circle is drawn.
  • A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.
  • The resulting four points on the circle are the vertices of the inscribed square.

Alicia deductions were;

Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle

Benjamin's deductions;

The diameters must be perpendicular to each other. Then connect the points, in order, around the circle

Caleb's deduction;

No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.

It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.

Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.

Learn more about an inscribed square here:

brainly.com/question/2458205

#SPJ1

6 0
2 years ago
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