Hello from MrBillDoesMath!
Answer:
3
Discussion:
34 + 2x = 40 => subtract 34 from both sides
(34-34) + 2x = 40 - 34 => as (34-34) = 0 and 40-34 = 6
2x = 6 => divide both sides by 2
x = 6/2 = 3
Check the answer:
Does 34 + 2x = 40 if x = 3 ?
Does 34 + 2(3) = 40 ?
Does 34 + 6 = 40 ? YES! so the answer checks.
Thank you,
MrB
Answer:
2162.2 degrees Celsius
Step-by-step explanation:
Celsius (°C) = (Fahrenheit - 32) / 1.8
3924-32 = 3892
3982 / 1.8 = 2162.2222222222222222222222
Rounded is 2162.2
Answer:
4 × (3 + 7) = (4 ×7) + (4 × 3)
Step-by-step explanation:
If you go by the order of PEMDAS you would do the parentheses first. 3 + 7 =10. 10 × 4 = 40. Then you would just use the distributive property and do (4× 7) + (4 × 3)
4 × 7 = 28 and 4 × 3 = 12 28 +12 =40
Answer:
Option C
Step-by-step explanation:
- For the matrix A of order
to be invertible, its determinant must not be equal to zero, |A| 
0, 
exists if- AC = CA = I, where I is identity matrix.
- The homogeneous equation with coefficient matrix A has a unique solution:
AB = 0, B = 
Thus, B = (0, 0, 0......., 0) is a unique solution
2. The non - homogeneous equation system with coefficient matrix A has a unique solution:
For an equation- AY = D
Y = 
is a unique solution
3. Every non homogeneous equation with coefficient matrix A is not consistent as:
For an equation- AY = D, has a solution.l Thus coefficient matrix is inconsistent whereas augmented matrix is.
4. Rank of matrix A = n, Thus the column space of A is 
5. Since, column space of A = , thus x→xA is one-to-one
Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
<h3>
Inscribing a square</h3>
The steps involved in inscribing a square in a circle include;
- A diameter of the circle is drawn.
- A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.
- The resulting four points on the circle are the vertices of the inscribed square.
Alicia deductions were;
Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle
Benjamin's deductions;
The diameters must be perpendicular to each other. Then connect the points, in order, around the circle
Caleb's deduction;
No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.
It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.
Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
Learn more about an inscribed square here:
brainly.com/question/2458205
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