All categories

2 years ago

Pls help. I offer 50. A. 3.6 B. 3.8 C. 3.9 D. 4.0

Mathematics

2 answers:

Nata [24]2 years ago

7 0

Answer:

$\pmb{3.8 }$

Step-by-step explanation:

we have to find the value of the expected egg production for any one egg.

That is,

3*0.25+4*0.7*5*0.05
0.75+2.8+0.25
3.8

Hence,

OPTION B IS CORRECT.

lianna [129]2 years ago

3 0

Answer:

B. 3.8

Step-by-step explanation:

Expected egg production is:

3*0.25+4*0.7+5*0.05 = 3.8

Correct choice is B

You might be interested in

Given points A(-3, 2), B(7, 8), and C(10,3) of parallelogram ABCD, find the coordinates of D that complete the parallelogram cor

dlinn [17]

I believe it is(0,-3)

6 0

2 years ago

What is 83 + 119 + 17 =

Fittoniya [83]

Answer:

219

Step-by-step explanation:

83 + 119 = 202

202 + 17 = 219

3 0

2 years ago

Read 2 more answers

A wheel with a circumference of 3 inches is rotating at 5 rotations per minute. I is the distance the wheel travels in one minut

Andreas93 [3]

So circumference is the distance around the wheel
that is the part that is actually touching the ground
so therefor the wheele travels 3 inches per rotations
5 rotations per minute
we have to find the distance
3 times (number of roations) times 1 minute=3 times 5 times 1=15
answer is 15 in per miute
I=15

7 0

2 years ago

Find the difference between8/15 and 2/3 Show all calculations in your final answer.

kherson [118]

Answer:

$\frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}$

Step-by-step explanation:

Let the value of a number 'a' be = 8/15

Let the value of a number 'b' be = 2/3

The difference between the two numbers can be calculated by subtracting the numbers

$a-b=\frac{8}{15}-\left(\frac{-2}{3}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\frac{8}{15}-\frac{-2}{3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=\frac{8}{15}-\left(-\frac{2}{3}\right)$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=\frac{8}{15}+\frac{2}{3}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{8+10}{15}$

$=\frac{18}{15}$

$\mathrm{Cancel\:the\:common\:factor:}\:3$

$=\frac{6}{5}$

Thus,

$\frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}$

3 0

2 years ago

if Dakota earned $15.75 in interest in account A and $28.00 in interest in account B after 21 months. if the simple interest rat

NISA [10]

keeping in mind that 21 months is more than a year, since there are 12 months in a year, then 21 months is really 21/12 years.

$\bf ~~~~~~ \stackrel{\textit{account A}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &15.75\\ P=\textit{original amount deposited}\dotfill \\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\to \frac{21}{12}\dotfill &\frac{7}{4} \end{cases} \\\\\\ 15.75=P(0.03)\left( \frac{7}{4} \right)\implies \cfrac{15.75}{(0.03)\left( \frac{7}{4} \right)}=P\implies \boxed{300=P}$

$\bf ~~~~~~ \stackrel{\textit{account B}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &28\\ P=\textit{original amount deposited}\dotfill \\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ t=years\to \frac{21}{12}\dotfill &\frac{7}{4} \end{cases} \\\\\\ 28=P(0.049)\left( \frac{7}{4} \right)\implies \cfrac{28}{(0.049)\left( \frac{7}{4} \right)}=P\implies \boxed{326.53\approx P}$

so, clearly, you can see who's greater.

3 0

3 years ago