1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
grandymaker [24]
2 years ago
11

Please help please please

Mathematics
2 answers:
Olegator [25]2 years ago
8 0
Profit. :) hope this helped
IrinaVladis [17]2 years ago
3 0

Answer: Profit

Step-by-step explanation:

1.  She made profit

2. She got 300 more than what she bought it for.

3. Her percentage was I think 25% more ( i am not sure on this one)

You might be interested in
For what value(s) of k will the relation not be a function
skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

k-8.3+2.4k=-\frac{3}{4} k

3.4k-8.3=-\frac{3}{4}k

3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10

4k-83=-\frac{15}{2}k

34k=-\frac{15}{2}k+83

\frac{83}{2}k=83

83k=166

k=2............Answer

(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

2-|k+1|=-6

2-\left|k+1\right|-2=-6-2

-\left|k+1\right|=-8

\left|k+1\right|=8

Since, this is absolute function

so, we can break it into two parts

|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a

k+1=-8\quad \quad \mathrm{or}\quad \:\quad \:k+1=8

we get

k+1=-8\quad

k=-9

k+1=8\quad

k=7

so,

k=-9\quad \mathrm{or}\quad \:k=7...............Answer

5 0
3 years ago
Create diagrams to represent the possible cases for common tangents between two circles. Your diagram can be created using multi
Anastaziya [24]

I made mine from google drawings

3 0
3 years ago
Given that f(x)= x2+3 and g(x)= x+4/3 solve for (f(g(x)) when x =2
Savatey [412]
\bf \begin{cases}
f(x)=x^2+3\\\\
g(x)=x+\cfrac{4}{3}
\end{cases}
\\\\\\
\boxed{x=2}\qquad g(2)=(2)+\cfrac{4}{3}\implies \boxed{g(2)=\cfrac{10}{3}}
\\\\\\
f(~~g(x)~~)=[g(x)]^2+3\implies f(~~g(2)~~)=[g(2)]^2+3
\\\\\\
f(~~g(2)~~)=\left[ \boxed{\frac{10}{3}} \right]^2+3\implies f(~~g(2)~~)=\cfrac{10^2}{3^2}+3
\\\\\\
f(~~g(2)~~)=\cfrac{100}{9}+3\implies f(~~g(2)~~)=\cfrac{100+27}{9}
\\\\\\
f(~~g(2)~~)=\cfrac{127}{9}
7 0
3 years ago
An artist is making a mosaic using glass
Rudik [331]

Answer:

200

the ratio is  1:2 i thought about how i could get a solution then i realized i could split the 600 in too three parts to match the ratios different aspects and walla i got 200

8 0
3 years ago
Read 2 more answers
Determine if the two triangles are congruent. If so, select the appropriate congruence postulate. If not, select the reason why.
morpeh [17]

Answer:

Asa

Step-by-step explanation:

Because if u look left to right on one triangle there is a angle and in between they have a com on line and on the right theres another angle so There for it’s angle side angle

4 0
2 years ago
Other questions:
  • Lines b and c are parallel. What is the measure of Angle6?
    13·1 answer
  • If the points(1,2),(2,6),and (3,y) are on line L, then y = <br> A)6 <br> B)8<br> C)10<br> D)12
    9·1 answer
  • A jet boat is used to take canoers 200 miles upriver to their starting point. As the driver of the jet boat, Jeremy knows that i
    6·2 answers
  • On Geometry, How can I do a 12-Pointed star?
    5·1 answer
  • How do you solve that (2cosx+1)(2cosx-1)(2cos2x-1)=2cos4x+1<br>Please help it's urgent!
    6·2 answers
  • Can someone help me
    8·1 answer
  • Overlapping triangles ​
    6·1 answer
  • A yoga instructor offers two options for classes.
    13·1 answer
  • What is the measure of ABC?
    15·1 answer
  • A number cube is rolled. What is the probability that a number greater than 4 will be rolled?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!