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Arte-miy333 [17]
3 years ago
15

Why do some element's symbols not match their name? Example: iron = Fe

Chemistry
2 answers:
Zinaida [17]3 years ago
6 0

Answer:

In the spirit of compromise, an element's name might come from one language, and its symbol from another. That's the case with tungsten. Its symbol is W, says Kean, “because the Germans call the element 'wolfram. ' It was a compromise between different countries' claims

kondaur [170]3 years ago
3 0
The symbol might be in one language and the name another. For example Fe is irons symbol. Fe is ferrum, iron in Latin.
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Ag2O(s) → 2Ag(s) + ½ O2(g) ΔH° = 31.05 kJ Which statements concerning the reaction above are true? (1) heat is released (2) heat
Sidana [21]

Answer:

D) 2, 4, and 5

Explanation:

In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.

If heat is absorbed in a reaction, that reaction is endothermic.

Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.

5 0
4 years ago
A sample of iron receives 50 J of heat energy that raises the temperature of the iron to a delta T of 25.0°C. If iron has a spec
svlad2 [7]

Answer: 20 g

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Q= 50J , dT= 25 C anc c= 0.10 J / g C

And m = Q / c dT

6 0
3 years ago
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Elina [12.6K]

Answer:

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3 0
3 years ago
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which factor would increase the carrying capacity for a white-tailed deer in an eastern temperate forest ecosystem
saveliy_v [14]
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4 0
3 years ago
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Hydrogen sulfide decomposes according to the following reaction, 2 H2S(g) → 2 H2(g) + S2(g) where ∆S = +78.1 J/K, ∆H = +169.4 kJ
arlik [135]

Answer:

The reaction is spontaneous when T > 2170 K.

Explanation:

The spontaneity of a reaction is related to the standard Gibbs free energy (ΔG°). When ΔG° < 0 the reaction is spontaneous. ΔG° is related to the standard enthalpy (ΔH°) and the standard entropy (ΔS°) through the following expression:

ΔG° = ΔH° - T.ΔS°

where,

T is the absolute temperature

The reaction is spontaneous when ΔG° < 0, that is,

ΔH° - T.ΔS° < 0

ΔH° <  T.ΔS°

T > ΔH°/ΔS° = (169.4 × 10³ J)/(78.1 J/K) = 2170 K

The reaction is spontaneous when T > 2170 K.

7 0
4 years ago
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