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3 years ago

Why do some element's symbols not match their name? Example: iron = Fe

Chemistry

2 answers:

Zinaida [17]3 years ago

6 0

Answer:

In the spirit of compromise, an element's name might come from one language, and its symbol from another. That's the case with tungsten. Its symbol is W, says Kean, “because the Germans call the element 'wolfram. ' It was a compromise between different countries' claims

kondaur [170]3 years ago

3 0

The symbol might be in one language and the name another. For example Fe is irons symbol. Fe is ferrum, iron in Latin.

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What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91

Vikentia [17]

Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen $(O_2)$ if it occupies 31.6 mL at $91^{o}C$ .

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

$1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L$

Temperature = $91^{o}C = (91 + 273) K = 364 K$

As molar mass of $O_2$ is 32 g/mol. Hence, the number of moles of $O_2$ are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol$

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

$PV = nRT\\P \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm$

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen $(O_2)$ if it occupies 31.6 mL at $91^{o}C$ .

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Which of the following best describes the neutron?

Setler [38]

The particles that combined in the middle of the structure best describes neutron as neutron is always present in the middle of atomic structure

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Trey was asked to build a working model of a landform for a science project. He chose to build a model of a volcano.

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3 years ago

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In a 0.01 M solution of 1,4-butanedicarboxylic acid, HOOCCH2CH2COOH (Ka1 = 2.9 x 10-5,

azamat

Answer:

The correct answer is B) HOOCCH2CH2COOH(aq)

Explanation:

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