A compound contains 38.7% K, 13.9% N, and 47.4% O by mass. What is the empirical formula of the compound?

1 answer:

8 0

K ---> 38.7 g / 39.1 g/mol = 0.99
N ---> 13.9 g / 14.0 g/mol = 0.99
O ---> 47.4 g / 16.0 g/mol = 2.96

Divide by smallest:

K ---> 0.99 / 0.99 = 1
N ---> 0.99 / 0.99 = 1
O ---> 2.96 / 0.99 = 3

KNO3

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