I first converted the given grams of the reactants into moles, and then divided the moles by the coefficients in front of each of the reactant. The result with the smallest value will be the limiting reactant, and the value of CuO was the smallest, so it's the limiting reactant.

After figuring out which reactant is the limiting one, I took their given grams and converted it into moles, the divided it by the ratio of N2 to CuO (it's in the equation) to obtain the moles of N2, and then multiply it with the molar mass of N2 to get its mass in grams.

6 0

3 years ago

A single alkyl bromide reactant theoretically yields either of the given products, depending on the reaction conditions. Draw th

Ierofanga [76]

Answer:

$H_{3}C$ -- $H_{3}C$ -- $CH_{3}$ --Br-- $CH_{3}$

Explanation:

The steps involved in predicting the structure of the alkyl bromide compound are outlined below.

1) An examination of the product shows that the product could only be formed by a substitution reaction.

2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.

Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is $H_{3}C$ -- $H_{3}C$ -- $CH_{3}$ --Br-- $CH_{3}$ . A pictorial diagram of the alkyl bromide compound is also attached.

8 0

3 years ago

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E. Which of the following is a mixture? i. Water ii. Hydrogen iii. Air iv. Iron​

E. Which of the following is a mixture? i. Water ii. Hydrogen iii. Air iv. Iron