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RoseWind [281]
3 years ago
6

Which of the following best describes the neutron?

Chemistry
1 answer:
Setler [38]3 years ago
7 0
The particles that combined in the middle of the structure best describes neutron as neutron is always present in the middle of atomic structure
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A student is doing online research. The student's teacher said that some
adoni [48]
Websites that end in .com or .org should be avoided.
3 0
3 years ago
Match the following descriptions with the correct polysaccharide, note if you answer any part of this question incorrectly a sig
Ad libitum [116K]

Answer:

Glycogen. Cellulose. Amylose. Cellulose. Amylopetin and Glycogen. Amylopetin and Cellulose.

Explanation:

Glycogen is the form that glucose is stored in human body.

Cellulose is the structural part of plant cell walls and human cannot digest it.

Amylose is the polysaccharide linked mainly by the the bonds of \alpha 1,4 glycosidic.

Cellulose is an unbranched polysaccharide linked mainly by the bonds of  \beta 1,4 glycosidic.

Amylopetin and Glycogen are branched polysaccharides linked by the bonds of \alpha 1,4 glycosidic and \alpha 1,6 glycosidic.

Amylopetin and Cellulose are mainly stored in plants.

4 0
3 years ago
According to boyle’s law, when the pressure on a gas in an enclosed container increases, the volume of that gas
Doss [256]
Decreases. Hope I helped
3 0
3 years ago
Alex built a model to show how light bends when placed into water. To do this, Alex filled a fish tank up with water, and shined
densk [106]

Answer:

The model cannot show how light bends.

Explanation:

4 0
3 years ago
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

5 0
2 years ago
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