Answer:
see explanation
Step-by-step explanation:
(1)
f(g(x))
Substitute x = g(x) into f(x)
f(3x + 1)
= 2(3x + 1) + 4
= 6x + 2 + 4
= 6x + 6
(2)
Evaluate f(2) then substitute the value obtained into g(x)
f(2) = 2x + 4 = 2(2) + 4 = 4 + 4 = 8 , then
g(8) = 3x + 1 = 3(8) + 1 = 24 + 1 = 25
(3)
(g ￮ f )(x)
= g(f(x))
= g(2x + 4)
= 3(2x + 4) + 1
= 6x + 12 + 1
= 6x + 13
g(2) means plug in x = 2 into the function g(x) = |-2x + 4| and f(-1) means plug x = -1 into f(x) = 3x - 1.
That will give you two numbers that you can then use to calculate g(2) - f(-1)
Its 1
Doubled:-
7
Do the brackets first
X+8= 8x
then you plus 8x + 8x =16x
16x -9 =7x
