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SOVA2 [1]
3 years ago
13

The y-intercept of any straight non-vertical line refers to the y-value of the point where the line crosses the y-axis - that is

, where the x-coordinate is zero.
This can be (choose all that apply)



Group of answer choices

the change of the y-coordinates divided by the change in the x-coordinates

be always the location of the line in the xy coordinate system-that is, where the line hits the y-axis.

always be the location of the line in the xy coordinate system where the line hits the x-axis

the initial value of the output variable when the input variable is time. The y-intercept has an x-coordinate of zero, so if the input variable is time, the y-intercept is referred to as the starting value.
Mathematics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

see below

Step-by-step explanation:

<u>Answer choices:</u>

A. the change of the y-coordinates divided by the change in the x-coordinates

  • slope

B. be always the location of the line in the xy coordinate system-that is, where the line hits the y-axis.

  • y-intercept

C. always be the location of the line in the xy coordinate system where the line hits the x-axis

  • x-intercept

D. the initial value of the output variable when the input variable is time. The y-intercept has an x-coordinate of zero, so if the input variable is time, the y-intercept is referred to as the starting value.

  • y-intercept
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How many integers are there that consist of four digits (from 1000 to 9999) where the first digit is a 5 or an 8 and the third d
Ostrovityanka [42]

Answer:

1600 integers

Step-by-step explanation:

Since we have a four digit number, there are four digit placements.

For the first digit, since there can either be a 5 or an 8, we have the arrangement as ²P₁ = 2 ways.

For the second digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.

For the third digit, since it neither be a 5 or an 8, we have two less digit from the total of ten digits which is 10 - 2 = 8. So, the number of ways of arranging that is ⁸P₁ = 8.

For the last digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.

So, the number of integers that can be formed are 2 × 10 × 8 × 10 = 20 × 80 = 1600 integers

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ANSWER: D

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3 years ago
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