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SIZIF [17.4K]
3 years ago
5

Help me please asap..​

Mathematics
2 answers:
olga_2 [115]3 years ago
8 0

Answer:

Solution given:

Sin angle is given by opposite side to the hypotenuse

so

Sin E =opposite/hypotenuse=4/5

<u>option</u><u> </u><u>d</u><u>.</u><u>4</u><u>/</u><u>5</u>

kipiarov [429]3 years ago
6 0

Answer:

option c 5/3 fe cdjwwwww

Step-by-step explanation:

ok

You might be interested in
The equation for the circle is:
balu736 [363]

Answer:

(-7, -5)

Step-by-step explanation:

x² + y² + 14x + 10y − 7 = 0

Strategy:

Convert the equation to the centre-radius form:

(x - h)² + (y - k)² = r²

The centre of the circle is at (h, k) and the radius is r

Solution:

Group x and y terms together; move the number to the right-hand side.

x² + 14x + y² + 10y = 7

Complete the square for x

(Take half the coefficient of x, square it, and add to each side of the equation)

(14/2)² = 7² = 49

(x² + 14x + 49) + (y² + 10y) = 56

Complete the square for y

(Take half the coefficient of y, square it, and add to each side of the equation)

(10/2)² = 5² =25

(x² + 14x + 49) + (y² + 10y + 25 ) = 81

Express the result as the sum of squares

(x + 7)² + (y + 5)² = 9²

h = -7; k = -5; r = 9

The centre of the circle is at (-7, -5).

The graph of the circle below has its centre at (-7, -5) and radius 9.

3 0
4 years ago
Can anybody answer this question?<br>I still don't understand maths​
meriva

Step-by-step explanation:

\frac{3}{x - 4}   =  \frac{2}{x + 1}  \\3 (x + 1) = 2(x - 4) \\ 3x + 3 = 2x - 8 \\ 3x - 2x =  - 8 - 3 \\ x =  - 11

6 0
3 years ago
3 3⁄10 - 2 23⁄100 = please help
Charra [1.4K]

Answer:

107/100 or 1 7/100 or 1.07

Step-by-step explanation:

Turn into improper fraction: 33/10 - 223/100

Find LCM: which is 10 because 10*10 = 100 and make common denominators

330/100 - 223/100 = 107/100 or 1 7/100

Hope this helped!

5 0
3 years ago
Read 2 more answers
Given one of the roots of the quadratic equation px2- 4x + 3p -8 =0 is 1 . Calculate the value of p
Natali [406]

Answer:

Value of p is 3

Step-by-step explanation:

One of the root is 1.

So, putting 1 in the place of x in the given equation,

px²-4x+3p-8=0

or, p-4+3p-8=0

or, 4p-12=0

or, 4p=12

or, p=3

Answered by GAUTHMATH

7 0
3 years ago
2,17,82,257,626,1297 next one please ?​
In-s [12.5K]

The easy thing to do is notice that 1^4 = 1, 2^4 = 16, 3^4 = 81, and so on, so the sequence follows the rule n^4+1. The next number would then be fourth power of 7 plus 1, or 2402.

And the harder way: Denote the <em>n</em>-th term in this sequence by a_n, and denote the given sequence by \{a_n\}_{n\ge1}.

Let b_n denote the <em>n</em>-th term in the sequence of forward differences of \{a_n\}, defined by

b_n=a_{n+1}-a_n

for <em>n</em> ≥ 1. That is, \{b_n\} is the sequence with

b_1=a_2-a_1=17-2=15

b_2=a_3-a_2=82-17=65

b_3=a_4-a_3=175

b_4=a_5-a_4=369

b_5=a_6-a_5=671

and so on.

Next, let c_n denote the <em>n</em>-th term of the differences of \{b_n\}, i.e. for <em>n</em> ≥ 1,

c_n=b_{n+1}-b_n

so that

c_1=b_2-b_1=65-15=50

c_2=110

c_3=194

c_4=302

etc.

Again: let d_n denote the <em>n</em>-th difference of \{c_n\}:

d_n=c_{n+1}-c_n

d_1=c_2-c_1=60

d_2=84

d_3=108

etc.

One more time: let e_n denote the <em>n</em>-th difference of \{d_n\}:

e_n=d_{n+1}-d_n

e_1=d_2-d_1=24

e_2=24

etc.

The fact that these last differences are constant is a good sign that e_n=24 for all <em>n</em> ≥ 1. Assuming this, we would see that \{d_n\} is an arithmetic sequence given recursively by

\begin{cases}d_1=60\\d_{n+1}=d_n+24&\text{for }n>1\end{cases}

and we can easily find the explicit rule:

d_2=d_1+24

d_3=d_2+24=d_1+24\cdot2

d_4=d_3+24=d_1+24\cdot3

and so on, up to

d_n=d_1+24(n-1)

d_n=24n+36

Use the same strategy to find a closed form for \{c_n\}, then for \{b_n\}, and finally \{a_n\}.

\begin{cases}c_1=50\\c_{n+1}=c_n+24n+36&\text{for }n>1\end{cases}

c_2=c_1+24\cdot1+36

c_3=c_2+24\cdot2+36=c_1+24(1+2)+36\cdot2

c_4=c_3+24\cdot3+36=c_1+24(1+2+3)+36\cdot3

and so on, up to

c_n=c_1+24(1+2+3+\cdots+(n-1))+36(n-1)

Recall the formula for the sum of consecutive integers:

1+2+3+\cdots+n=\displaystyle\sum_{k=1}^nk=\frac{n(n+1)}2

\implies c_n=c_1+\dfrac{24(n-1)n}2+36(n-1)

\implies c_n=12n^2+24n+14

\begin{cases}b_1=15\\b_{n+1}=b_n+12n^2+24n+14&\text{for }n>1\end{cases}

b_2=b_1+12\cdot1^2+24\cdot1+14

b_3=b_2+12\cdot2^2+24\cdot2+14=b_1+12(1^2+2^2)+24(1+2)+14\cdot2

b_4=b_3+12\cdot3^2+24\cdot3+14=b_1+12(1^2+2^2+3^2)+24(1+2+3)+14\cdot3

and so on, up to

b_n=b_1+12(1^2+2^2+3^2+\cdots+(n-1)^2)+24(1+2+3+\cdots+(n-1))+14(n-1)

Recall the formula for the sum of squares of consecutive integers:

1^2+2^2+3^2+\cdots+n^2=\displaystyle\sum_{k=1}^nk^2=\frac{n(n+1)(2n+1)}6

\implies b_n=15+\dfrac{12(n-1)n(2(n-1)+1)}6+\dfrac{24(n-1)n}2+14(n-1)

\implies b_n=4n^3+6n^2+4n+1

\begin{cases}a_1=2\\a_{n+1}=a_n+4n^3+6n^2+4n+1&\text{for }n>1\end{cases}

a_2=a_1+4\cdot1^3+6\cdot1^2+4\cdot1+1

a_3=a_2+4(1^3+2^3)+6(1^2+2^2)+4(1+2)+1\cdot2

a_4=a_3+4(1^3+2^3+3^3)+6(1^2+2^2+3^2)+4(1+2+3)+1\cdot3

\implies a_n=a_1+4\displaystyle\sum_{k=1}^3k^3+6\sum_{k=1}^3k^2+4\sum_{k=1}^3k+\sum_{k=1}^{n-1}1

\displaystyle\sum_{k=1}^nk^3=\frac{n^2(n+1)^2}4

\implies a_n=2+\dfrac{4(n-1)^2n^2}4+\dfrac{6(n-1)n(2n)}6+\dfrac{4(n-1)n}2+(n-1)

\implies a_n=n^4+1

4 0
3 years ago
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