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Veronika [31]
3 years ago
5

20 point if you answer all questions

Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

13/8 45/3/8  7 7/8

Step-by-step explanation:

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3 0
2 years ago
According to the Bureau of Labor Statistics, the average weekly pay for a U.S. production worker was $441.84. Assume that availa
tensa zangetsu [6.8K]

Answer:

41.94% probability that a worker earned between $400 and $500.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 441.84, \sigma = 90

What is the probability that a worker earned between $400 and $500?

This is the pvalue of Z when X = 500 subtracted by the pvalue of Z when X = 400. So

X = 500

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 441.84}{90}

Z = 0.65

Z = 0.65 has a pvalue of 0.7422

X = 400

Z = \frac{X - \mu}{\sigma}

Z = \frac{400 - 441.84}{90}

Z = 0.65

Z = -0.46 has a pvalue of 0.3228

So there is a 0.7422 - 0.3228 = 0.4194 = 41.94% probability that a worker earned between $400 and $500.

7 0
4 years ago
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