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3 years ago

Answer choices:

Mathematics

1 answer:

pychu [463]3 years ago

4 0

Answer:

B. 15

Step-by-step explanation:

The chances of randomly selecting keys for a sports car or convertible is 5/40 since there are a total of 5 sports and convertible car keys and a total of 40 keys overall. We then multiply that 5/40 by 120 because Sam randomly selects a key 120 times.

5/40 × 120 = 15

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15 and 17 pls.. 15 points!!!!

Maurinko [17]

Step-by-step explanation:

15) 50 ÷ 2 = 25

17) Mean = 301, Mode = 40-50

(10+20) ÷ 2 = 15, (20+30) ÷ 2 = 25, (30+40) ÷ 2 = 35

(40+50) ÷ 2 = 45, (50+60) ÷ 2 = 55, (60+70) ÷ 2 = 65

(70+80) ÷ 2 = 75

• 15×4 = 60, 25×8 = 200, 35×10 = 350, 45×12 = 540

55×10 = 550, 65×4 = 260, 75×2 = 150

Mean = (60+200+350+540+550+260+150) ÷ 7

= 2110 ÷ 7

= 301.4285....

= 301

Mode : the highest frequency

3 0

3 years ago

Read 2 more answers

Ignore circled one and work it out please

mash [69]

Answer:

a. $\frac{(x-7)}{x^2+x-30}$

Step-by-step explanation:

$\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}$

3 0

3 years ago

The total number of people who visitedthe ocean adventure park last year was 7,040,836 . What is the valur of the digit 4 in thi

Vesna [10]

The total number of people who visitedthe ocean adventure park last year was 7,040,836

In 7,040,836, there are FOUR digits after 4.

To find value of 4, just put FOUR zeroes after 4

Thus, Value of 4 = 40000

5 0

3 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.