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BartSMP [9]
3 years ago
12

I need help plzzzzzzzz

Mathematics
1 answer:
melamori03 [73]3 years ago
3 0

Answer:

A: y=3x-3

Step-by-step explanation:

Use slope formula and slope-intercept form:

y=mx+b

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Pracuco shoot #2
Pani-rosa [81]

Answer:

4 teaspoons of salt.

Step-by-step explanation:

2+2=4

7 0
3 years ago
Please help me with this one too
lozanna [386]

Try B that’s what i got

4 0
3 years ago
What is m-a = n+p, for a
sergeinik [125]

Answer:

A=m-n-p

Step-by-step explanation:

So solve for a, we have to isolate it on one side, so -a=n+p-m. So a=m-n-p

5 0
3 years ago
Read 2 more answers
central angle of a sector is 72° and the sector has an area of 16.2(pie) ft^2. what is the radius of the circle?
Cloud [144]
Sector area = (central angle / 360) * PI * radius^2
sector area = (72 / 360) * PI * radius^2
radius^2 = sector area / [(72 / 360) * PI]
radius^2 = 16.2 * PI / [(1 / 5) * PI]
radius^2 = 16.2 / .2
radius^2 = 81
radius = 9

Source:
http://www.1728.org/radians.htm



6 0
4 years ago
\[f(x)=\sqrt{x ^4-16x ^{2}}\]
marusya05 [52]
f ( x ) =  \sqrt{ x^{4} -16 x^{2} }
a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )
b ) f ` ( x ) = \frac{1}{2 \sqrt{x ^{4}-16 x^{2}  } } *  ( x^{4}-16 x^{2} )` =
= ( 2 x³ - 16 x ) / √(x^4 - 16 x²)
c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34 
4 0
3 years ago
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