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3 years ago

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Ana is working at her sister's pizzeria researching the preparation of different pizza dough recipes. A sample of 27 recipes rev

ealed the following information regarding the linear relationship between cost ($/lb) and preparation time (min).
Computer Regression Output for Preparation Time (min) vs. Cost ($/lb)

Predictor Coef SE Coef T P

Constant 18.7095 0.0634 295.31 0.0

Cost -3.9967 0.0384 -104.0 0.0

S = 0.033 R-Sq = 94.24% R-Sq (Adj) = 94.009%

a. Find the equation of the Least Squares Regression Line (LSRL).

b. Using an x-axis and y-axis, create a beautiful graph of the LSRL.

c. Calculate r, the correlation coefficient.

1 answer:

tino4ka555 [31]3 years ago

3 0

Answer:

after a doctor nice to meet you at the

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Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

<h3>16</h3>

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

<h3>17</h3>

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

<h3>18</h3>

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .

<h3>15</h3>

For triangle DEF:

The length of segment DF is to be found,
The length of segment EF is 9,
The sine of angle E is $\sin{64\textdegree}}$ , and
The sine of angle D is $\sin{39\textdegree}$ .

Apply the law of sine:

$\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}$

$\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9$ .

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3 years ago

Please help me thank you

laila [671]

Parallel lines have the same slope. The equation of the parallel line is therefore:

y = x + b

Plug in the values you are given to find b:

2 = -3 + b

b = 5

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2 years ago

X=4y-5<br> 2x+3y=23<br> Solve using the substitution method

jenyasd209 [6]

Answer:

x =7, y = 3

Step-by-step explanation:

We substitute the value of x in terms of y (given) into the equation.

Then we solve for y and plug in the value of y back into the equation for the value of x to find x.

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If if the branding division were to experience the same percentage increase from year 2 to year 3 as they did from year 1 to yea

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Since the basis is from year 1 to year 2, calculate first for the difference of their percentages. That would be:

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We apply this same value of percentage increase from year 2 to year. Thus, the percentage for year 3 is:

% Year 3 = % Year 2 + percentage increase
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A bag contains 5 red marbles, 3 green marbles, 2 purple marbles, 2 orange marbles, and 1 blue marble.

san4es73 [151]

The answer is blue i just took the test.

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3 years ago

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