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Pepsi [2]
3 years ago
9

Pleaseeee helpp answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Pavel [41]3 years ago
5 0

Answer:

x = 87º

Step-by-step explanation:

opposing angles in quadrilaterals are equal, so x = 87º

blsea [12.9K]3 years ago
3 0

Answer:

Well the value should be 87 degrees, sorry if im incorrect but please mark me brainliest

Step-by-step explanation:

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4 16/17 as a improper fraction
Allushta [10]

Answer:

\frac{84}{17}

Step-by-step explanation:

  1. Formula for mixed number to improper fraction: (Whole number × denominator) + numerator
  2. 4 × 17 = 68, 68 + 16 = 84
  3. Re-write the fraction: \frac{84}{17}  

I hope this helps!

7 0
3 years ago
Read 2 more answers
How to solve? I basically want to know the first step..
inessss [21]
You have to get x alone and then do the rest of the steps
5 0
3 years ago
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What is the domain and range for this graph?
11Alexandr11 [23.1K]
Informally, the domain is the set of all possible elements in a set for which there is one and only one output. In interval notation, the domain is (-4, ∞). I am assuming it continues on infinitely to the right because of the arrow. The range is [1, <span>∞). Here, you choose the lowest value on the graph, up to the highest one.</span>
8 0
3 years ago
A 95% confidence interval for a population mean is computed from a sample of size 400. Another 95% confidence interval will be c
Anna [14]

Answer:

The interval from the sample of size 400 will be approximately <u>One -half as wide</u> as the interval from the sample of size 100

Step-by-step explanation:

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion

Generally the margin of error is mathematically represented as

      E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }    

Here assume that Z_{\frac{\alpha }{2} } \ and \  \sigma \ is constant so

     E =  \frac{k}{\sqrt{n} }

=>  E \sqrt{n} = K

=>   E_1 \sqrt{n}_1 =  E_2 \sqrt{n}_2

So  let  n_1 = 400 and n_2 =  100

=>   E_1 \sqrt{400} =  E_2 \sqrt{100}

=>  E_1 =  \frac{\sqrt{100} }{\sqrt{400} } E_2

=>  E_1 =  \frac{1}{2 } E_2

So From this we see that  the confidence interval for a sample size of 400 will be half that with a sample size of 100

   

     

   

7 0
2 years ago
Plz help will mark as brainliest
Maru [420]

Answer: the second option !!!

3 0
3 years ago
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