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Step2247 [10]
3 years ago
15

Draw the angle below in standard position. -3pi/4

Mathematics
1 answer:
andriy [413]3 years ago
8 0

First of all, the negative sign means that we will turn clockwise.

Since \frac{\pi}{4} is half a quarter, we have:

  • -\frac{\pi}{4} brings you at half of quadrant IV
  • -\frac{2\pi}{4} brings you on the negative side of the y axis
  • -\frac{3\pi}{4} brings you at half of quadrant III

So, option A is correct.

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Solve for x: x/3 = -48
oksano4ka [1.4K]

Answer:

-144

Step-by-step explanation:

x=-48 times 3

8 0
2 years ago
Read 2 more answers
Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = -5 - 5 cos θ
Grace [21]
Y-axis symmetry=(r, theta)=(-r,theta)
-5-5cos(theta)=r
-r=5+5cos(theta)
no y-axis symmetry
x-axis symmetry=(r,theta)=(r,-theta)
cosine is an even function, so yes it is symmetric around x-axis
origin symmetry=(r,theta)=(-r,theta) or (r, theta+pi)
no, as there is no y-axis symmetry

6 0
3 years ago
The total dinner bill for five persons at a restaurant was $203.25. What was the average cost per person in dollars ?
Norma-Jean [14]
Hello! To find the average of something, multiply the total of something by the number of units. In this case, we divide the total bill by 5 people to get the average cost per person. 203.25/5 is 40.65. There. The average cost of dinner per person was $40.65.
7 0
3 years ago
równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma
Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0
2 years ago
Which equation can be used to solve for b?<br> B<br> 5 cm<br> 10 cm<br> 30°
kati45 [8]

The Question is Incomplete The complete question with figure is below.

Answer:

Therefore the equation to solve for b is

\tan 30 = \dfrac{5}{b}

Step-by-step explanation:

Given:

In Right Angle Triangle ABC

∠C = 90°

BC = 5 cm

AB = 10 cm

∠A = 30°

To Find:

b = ?

Solution:

In Right Angle Triangle ABC Tangent identity we have

\tan A = \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}

Substituting the values we get

\tan 30 = \dfrac{BC}{AC}\\\\\tan 30 = \dfrac{5}{b}

Therefore the equation to solve for b is

\tan 30 = \dfrac{5}{b}

6 0
3 years ago
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